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4 years ago

Find the mean median and mode of the deta set 1,6,3,9,6,8,4,4,4

Mathematics

2 answers:

Firlakuza [10]4 years ago

4 0

Mode (most occurring) - 4
mean (average) - 8
median (middle number from least to greatest) - 4

Sveta_85 [38]4 years ago

4 0

1, 3, 4, 4, 4, 6, 6, 8, 9

Median: 4

Mode: 4

Mean: 5

Mean: 1 + 3 + 4 + 4 + 4 + 6 + 6 + 8 + 9 = 45/9 = 5

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The cuboid has volume 288cm^3 (a) the cuboid has a length 12 cm and a width 5cm Calculate the height of the cuboid (b) 1cm^3 of

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3 years ago

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In ΔUVW, w = 44 cm, u = 83 cm and ∠V=141°. Find the area of ΔUVW, to the nearest square centimeter.

Tema [17]

Answer:

$Area \approx 1149\ cm^2$

Step-by-step explanation:

Given that:

ΔUVW,

Side w = 44 cm, (It is the side opposite to $\angle W$ )

Side u = 83 cm (It is the side opposite to $\angle U$ )

and ∠V=141°

Please refer to the attached image with labeling of the triangle with the dimensions given.

Area of a triangle with two sides given and angle between the two sides can be formulated as:

$A = \dfrac{1}{2}\times a\times b\times sinC$

Where a and b are the two sides and

$\angle C$ is the angle between the sides a and b

Here we have a = w = 44cm

b = u = 44cm

and ∠C= ∠V=141

Putting the values to find the area:

$A = \dfrac{1}{2}\times 44\times 83\times sin141\\\Rightarrow A = \dfrac{1}{2} \times 3652 \times sin141\\\Rightarrow A =1826 \times 0.629\\\Rightarrow A \approx 1149\ cm^2$

So, the area of given triangle to the nearest square centimetre is:

$Area \approx 1149\ cm^2$

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4 years ago