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3 years ago

MATH FRACTIONS!! What is 3/4 divided by 5/6 how to solve it the step by step. I NEED IT

Mathematics

2 answers:

Reil [10]3 years ago

6 0

Answer:

9/10

Step-by-step explanation:

the rule says

$\frac{a}{b} /\frac{c}{d} =\frac{ad}{bc}$

so in our case

a=3

b=4

c=5

d=6

so the division is

$\frac{3*6}{4*5} \\\\=\frac{18}{20}$

we can simplify

$\frac{18}{20} \\\\=\frac{2(9)}{2(10)} \\\\=\frac{9}{10}$

that's our answer

I don't know if you need step by step of the rule, if you need let me know

vaieri [72.5K]3 years ago

4 0

Answer:

9/10

Step-by-step explanation:

hi again haha so basically apply what i already told you

flip 5/6 to 6/5 and change division to x

so 3/4 x 6/5 both 4 and 6 can be divided by 2 so ask how many times does 2 go into 4 and 6 so it simplifies to 3/2 x 3/5

multiply the both tops and bottoms to get 9/10 :)

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Please look at the attached image. Really need Help!! Who ever find answer first will get brainily.

nadya68 [22]

Answer:

27°

Step-by-step explanation:

XWY and VWY are supplementary

∴ XWY + VWY = 180°

∴ XWY = 180° - VWY

XYW and ZYW are supplementary

∴ XYW + ZYW = 180°

∴ XYW = 180° - ZYW

ΔXWY is a right triangle at X

∴ XWY + XYW = 90°

∴ 180° - VWY + 180° - ZYW = 90°

∴ 180° - 6x + 180° - 4x = 90°

∴ 360° - 10x = 90°

∴ 10x = 270°

∴ x = 27°

7 0

3 years ago

Read 2 more answers

Find the sale price of the item. Round to two decimal places if necessary. Original price: $71.00 Markdown: 33% The sale price i

soldi70 [24.7K]

Answer:

8. $35.10

9. $59.63

10. $13.43

11. $70

12. Take the percent you pay (100-the discount) as a decimal and multiply it by the regular price.

Step-by-step explanation:

For finding the price we pay during a sale, we focus on the percent we pay. If 22% off is the sale, then we spend 78% or 100-22-78. We use this percent byb multiplying the price with a decimal. We convert percents into decimals by dividing the percent number by 100. For example, 78% divided by 100 becomes 0.78.

8. Percent off is 22%. We pay 78%=0.78.

45(0.78)=$35.10

9. Percent off is 33%. We pay 67%=0.67.

89(0.67)=$59.63

10. Percent off is 44%. We pay 56%=0.56.

23.99(0.56)=$13.43

11. Percent off is 75%. We pay 25%=0.25.

279.99(0.25)=$70

12. See explanation above.

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3 years ago

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I have a trapezoid what is the answer for a 4 inches in height by8 inches in base

andrey2020 [161]

We need to find the other base also in order for us to find out what the area of this is.

4 0

3 years ago

Activity 4: Performance Task

Nookie1986 [14]

An arithmetic progression is simply a progression with a common difference among consecutive terms.

The sum of multiplies of 6 between 8 and 70 is 390
The sum of multiplies of 5 between 12 and 92 is 840
The sum of multiplies of 3 between 1 and 50 is 408
The sum of multiplies of 11 between 10 and 122 is 726
The sum of multiplies of 9 between 25 and 100 is 567
The sum of the first 20 terms is 630
The sum of the first 15 terms is 480
The sum of the first 32 terms is 3136
The sum of the first 27 terms is -486
The sum of the first 51 terms is 2193

(a) Sum of multiples of 6, between 8 and 70

There are 10 multiples of 6 between 8 and 70, and the first of them is 12.

This means that:

$\mathbf{a = 12}$

$\mathbf{n = 10}$

$\mathbf{d = 6}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{10} = \frac{10}2(2*12 + (10 - 1)6)}$

$\mathbf{S_{10} = 390}$

(b) Multiples of 5 between 12 and 92

There are 16 multiples of 5 between 12 and 92, and the first of them is 15.

This means that:

$\mathbf{a = 15}$

$\mathbf{n = 16}$

$\mathbf{d = 5}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{16} = \frac{16}2(2*15 + (16 - 1)5)}$

$\mathbf{S_{16} = 840}$

(c) Multiples of 3 between 1 and 50

There are 16 multiples of 3 between 1 and 50, and the first of them is 3.

This means that:

$\mathbf{a = 3}$

$\mathbf{n = 16}$

$\mathbf{d = 3}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{16} = \frac{16}2(2*3 + (16 - 1)3)}$

$\mathbf{S_{16} = 408}$

(d) Multiples of 11 between 10 and 122

There are 11 multiples of 11 between 10 and 122, and the first of them is 11.

This means that:

$\mathbf{a = 11}$

$\mathbf{n = 11}$

$\mathbf{d = 11}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{16} = \frac{11}2(2*11 + (11 - 1)11)}$

$\mathbf{S_{11} = 726}$

(e) Multiples of 9 between 25 and 100

There are 9 multiples of 9 between 25 and 100, and the first of them is 27.

This means that:

$\mathbf{a = 27}$

$\mathbf{n = 9}$

$\mathbf{d = 9}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{9} = \frac{9}2(2*27 + (9 - 1)9)}$

$\mathbf{S_{9} = 567}$

(f) Sum of first 20 terms

The given parameters are:

$\mathbf{a = 3}$

$\mathbf{d = 3}$

$\mathbf{n = 20}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{20} = \frac{20}2(2*3 + (20 - 1)3)}$

$\mathbf{S_{20} = 630}$

(f) Sum of first 15 terms

The given parameters are:

$\mathbf{a = 4}$

$\mathbf{d = 4}$

$\mathbf{n = 15}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{15} = \frac{15}2(2*4 + (15 - 1)4)}$

$\mathbf{S_{15} = 480}$

(g) Sum of first 32 terms

The given parameters are:

$\mathbf{a = 5}$

$\mathbf{d = 6}$

$\mathbf{n = 32}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{32} = \frac{32}2(2*5 + (32 - 1)6)}$

$\mathbf{S_{32} = 3136}$

(g) Sum of first 27 terms

The given parameters are:

$\mathbf{a = 8}$

$\mathbf{d = -2}$

$\mathbf{n = 27}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{27} = \frac{27}2(2*8 + (27 - 1)*-2)}$

$\mathbf{S_{27} = -486}$

(h) Sum of first 51 terms

The given parameters are:

$\mathbf{a = -7}$

$\mathbf{d = 2}$

$\mathbf{n = 51}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{51} = \frac{51}2(2*-7 + (51 - 1)*2)}$

$\mathbf{S_{51} = 2193}$

Read more about arithmetic progressions at:

brainly.com/question/13989292

4 0

2 years ago

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Please Help I will give you a lot of points if you do!

Maru [420]

Answer:

De Morgan's Theorem, T12, is a particularly powerful tool in digital design. The theorem explains that the complement of the product of all the terms is equal to the sum of the complement of each term. Likewise, the complement of the sum of all the terms is equal to the product of the complement of each term.

Step-by-step explanation:

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3 years ago