Hello :
<span>f(x)=x²+4x-5
</span><span>The axis of symmetry for a function in the form f(x)=x^2+4x-5 is x=-2 :
</span>f(x) = (x+2)² + b
f(x) x²+4x+4+b= x² +4x-5
4+b= -5
b = -9
the vertex is : (2 , -9)
|x| > -1 represents all real numbers.
Answer:
Step-by-step explanation:
y = -4x + 6.....switch x and y and solve for y
x = -4y + 6 ....subtract 6 from both sides
x - 6 = -4y....divide by -4 on both sides
(x - 6) / -4 = y or y = -1/4x + 3/2 <====
Sole for f by simplifying both sides of the equation then isolating the variable so that means f=-40 over 3 for number one
for the second equation you do the same thing you did for number one and the answer will be
b=8
Answer:
ummm where is the question anyway?
