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3 years ago

Solve similar triangles

Mathematics

2 answers:

nalin [4]3 years ago

5 0

Answer:

7.5 ?

Step-by-step explanation:

jeka943 years ago

4 0

Answer:

7.5

Step-by-step explanation:

We are given information that the two triangles are similar and we want to work out the length of "t" . Since these 2 triangles are similar, it means that a scale factor is used to enlarge the sides, we can work out the scale by dividing QP by LJ and RP by KJ so,

QP ÷ JK = 25 ÷ 5 = 5

RP ÷ JL = 22.5 ÷ 4.5 = 5

So we can see the scale factor is 5, now all we need to do is multiply the scale factor by 1.5 to find the value of t

1.5 × 5 = 7.5

The value of t is 7.5

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Can someone explain to me how to do question number 6 please?

slavikrds [6]

Hope this helps but try to do process of elimination.

7 0

2 years ago

Tamara and Clyde got different answers when dividing 2x4 + 7x3 – 18x2 + 11x – 2 by 2x2 – 3x + 1. Analyze their individual work.

lys-0071 [83]

Note: As you may have unintentionally missed to add the different answers, based on which we had to check who solved correctly between Tamara and Clyda's work.

But, I am actually solving the expression and you must note that whoever (between Tamara and Clyda's work) may have got the same answer or match the answer with mine, would be the one who solved correctly.

Answer:

We conclude that whoever (between Tamara and Clyda's work) may have got the answer as $x^2+5x-2$ after dividing $2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2$ by $2x^2\:-\:3x\:+\:1$ , would be the one who solved it correctly.

Step-by-step explanation:

Considering the expression

$2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2$

Lets divide the expression by $2x^2\:-\:3x\:+\:1$

Solution Steps:

$\frac{2x^4+7x^3-18x^2+11x-2}{2x^2-3x+1}$

Factorizing

$2x^4+7x^3-18x^2+11x-2:\quad \left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)$

$\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{2x^2-3x+1}$

Factorizing

$2x^2-3x+1:\quad \left(2x-1\right)\left(x-1\right)$

$\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{\left(2x-1\right)\left(x-1\right)}$

$\mathrm{Cancel\:}\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{\left(2x-1\right)\left(x-1\right)}:\quad x^2+5x-2$

$x^2+5x-2$

Thus,

$\frac{2x^4+7x^3-18x^2+11x-2}{2x^2-3x+1}=x^2+5x-2$

Therefore, we conclude that whoever (between Tamara and Clyda's work) may have got the answer as $x^2+5x-2$ after dividing $2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2$ by $2x^2\:-\:3x\:+\:1$ , would be the one who solved it correctly.

Keywords: expression, division

Learn more about expression division from brainly.com/question/1575482

#learnwithBrainly

3 0

3 years ago

Read 2 more answers

Evaluate 6(5-(6-5)-3

IrinaK [193]

Answer:

Step-by-step explanation:

Evaluate 6(5-(6-5)-3) = 6(5-1-3) {first solve innermost bracket}

= 6* (5-4) = 6*1 =6

4 0

3 years ago

Read 2 more answers

How do you factor 7+14

mote1985 [20]

You could factor a 7 out of 7 + 14 to get 7(1 + 2).

This would equal the same thing as 7 + 14, which is 21.

7 * 3 = 21.

21 can be factored like so:

1 * 21 = 21

3 * 7 = 21

5 0

3 years ago

If f(x) =2x and g(x) = cos(x) then g(f(π/2)) = ? Number 2 in picture

Romashka [77]

Answer:

(4) -1.

Step-by-step explanation:

First evaluate f(π/2) which is 2 * π/2 = π.

So g(f(π/2)) = g(π)

= cos π

= -1.

6 0

3 years ago