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elena-s [515]
3 years ago
7

Thirty six and nine thousandths greater then four tens

Mathematics
2 answers:
Tatiana [17]3 years ago
3 0
Yes, because the whole number 36 is greater than 0.
36.009 > 0.4
ivanzaharov [21]3 years ago
3 0

Answer:

Yes, thirty six and nine thousandths is greater than four tenths

Step-by-step explanation:

Thirty six and nine thousandths greater then four tens

Thirty six is 36

nine thousandths  is 9 times 1/1000 is equal to 0.009

Thirty six and nine thousandths =36+0.009= 36.009

four tenths is 4 times 1/10 is equal to 0.4

now we compare 36.009 and 0.4

36 is greater than 0.4

So, 36.009 is greater than 0.4

Yes, thirty six and nine thousandths is greater than four tenths

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Jack knows the surface area of a cylinder and its radius. He wants to find the cylinder's height. He needs to rewrite the formul
mash [69]

Answer:

h = A/πr²

Step-by-step explanation:

Surface area (A) of a cylinder = πr² × height (h) , where r is the radius.

h = A ÷ πr² = A/πr²

7 0
3 years ago
The image of the point (2, 1) under a translation is (5, -3). Find
Yanka [14]

Answer:

The coordinates of the image of the point (6,6) under the same  translation is: (9, 2)

Hence, option C is correct.

Step-by-step explanation:

The image of the point (2, 1) under a translation is (5, -3).

It means when we horizontally move 3 units to the RIGHT i.e. adding 3 units to the x-coordinate and vertically move 4 units DOWN i.e. subtracting 4 units from the y-coordinate of the original point (2, 1), we get the coordinates of the image (5, -3).

Thus,

The rule of translation can be formulated such as:

(x, y) → (x + 3, y - 4)

(2, 1) → (2 + 3, 1 - 4) → (5, -3)

Thus,

Under the same rule of translation, we can determine the coordinates of the image of the point (6,6):

(x, y) → (x + 3, y - 4)

(6, 6) → (6 + 3, 6 - 4) → (9, 2)

Therefore, the coordinates of the image of the point (6,6) under the same  translation is: (9, 2)

Hence, option C is correct.

4 0
3 years ago
3x+1=7-4y solve for y pls help lol
Westkost [7]

Answer:

y = -3x/4+3/2

Step-by-step explanation:

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g100num [7]

Answer:

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Step-by-step explanation:

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Find the polynomial f(x) of degree 3 with real coefficients that has a y-intercept of 60 and zeros 3 and 1+3i.
Sauron [17]

\bf \begin{cases} x=3\implies &x-3=0\\ x=1+3i\implies &x-1-3i=0\\ x=1-3i\implies &x-1+3i=0 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ (x-3)(x-1-3i)(x-1+3i)=0 \\\\\\ (x-3)\underset{\textit{difference of squares}}{([x-1]-3i)([x-1]+3i)}=0\implies (x-3)([x-1]^2-[3i]^2)=0 \\\\\\ (x-3)([x^2-2x+1]-[3^2i^2])=0\implies (x-3)([x^2-2x+1]-[9(-1)])=0

[ correction added, Thanks to @stef68 ]

\bf (x-3)([x^2-2x+1]+9)=0\implies (x-3)(x^2-2x+10)=0 \\\\\\ x^3-2x^2+10x-3x^2+6x-30=0\implies x^3-5x^2+16x-30=f(x) \\\\\\ \stackrel{\textit{applying a translation with a -2f(x)}}{-2(x^3-5x^2+16x-30)=f(x)}\implies -2x^3+10x^2-32x+60=f(x)

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3 years ago
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