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alexandr1967 [171]
3 years ago
10

What is the solution for 5x^2-x+6=0

Mathematics
1 answer:
kati45 [8]3 years ago
7 0

The easiest way to solve this problem is by using the Pythagorean theorem :D

Pythagorean theorem: [-b +- sqrt(b^2 - 4ac)]/2a

5 = a

-1 = b

6 = c

therefore, by plugging these values in!

[-(-1) +- sqrt((-1)^2 - 4(5)(6))]/2(5)

[1 +- sqrt(1 - 120)]/10

Oh so we're using imaginary numbers, so in this case you'll need to know that i = sqrt(-1), so keep this in mind (I can see why this was so difficult)

[1 +- sqrt(119)*i]10

answers:

( 1 + i*sqrt(119) ) / 10

( 1 - i*sqrt(119) ) / 10

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Carina begins to solve the equation -4 - 2/3x = -6 by adding 4 to both sides. Which statements regarding the rest of the solving
Andru [333]

Answer:

A.) After adding 4 to both sides, the equation is -\frac{2}{3}x=-2

C.) The equation can be solved for x using exactly one more step by multiplying both sides by -\frac{3}{2}

D.) The equation can be solved for x using exactly one more step by dividing both sides by -\frac{2}{3}

Step-by-step explanation:

The correct questions is as follows:

Carina begins to solve the equation -4-2/3x=-6 by adding 4 to both sides. Which statements regarding the rest of the solving process could be true? Check all that apply.

A.) After adding 4 to both sides, the equation is -2/3x=-2.

B.) After adding 4 to both sides, the equation is -2/3x=-10 .

C.) The equation can be solved for x using exactly one more step by multiplying both sides by -3/2.

D.) The equation can be solved for x using exactly one more step by dividing both sides by -2/3.

E.) The equation can be solved for x using exactly one more step by multiplying both sides by -2/3.

Given equation:

-4-\frac{2}{3}x=-6

To show the steps we will carry out in order to solve for x

Solution:

Solving for x

Step 1:

Adding both sides by 4

4-4-\frac{2}{3}x=-6+4

Thus, we get:

-\frac{2}{3}x=-2

Thus statement A is correct.

Step 2:

Multiplying both sides by -\frac{3}{2}

-\frac{3}{2}\times -\frac{2}{3}x=-2\times -\frac{3}{2}

Thus, we get:

x=3  [Two negatives multiply to give a positive]

This proves that statement C is correct.

Or Step 2:

Dividing both sides by -\frac{2}{3}

\frac{-\frac{2}{3}x}{-\frac{2}{3}}=\frac{-2}{-\frac{2}{3}}

Thus, we get:

x=-2\times -\frac{3}{2} [On dividing with a fractional divisor, we take reciprocal and multiply it with the dividend.]

x=3  [Two negatives multiply to give a positive]

This prove that statement D is correct.

5 0
3 years ago
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