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3 years ago

ILL MARK BRAINLIEST Simplify the expression below. 10−2⋅32+13

Mathematics

2 answers:

riadik2000 [5.3K]3 years ago

4 0

Answer:

if you are multiplying the 2 and the 32, the answer would be -41

Step-by-step explanation:

hope this helps! :) :) :) (please give me brainliest!)

LUCKY_DIMON [66]3 years ago

4 0

Answer:

- 41

Step-by-step explanation:

10 - 2 · 32 + 13

Multiply first because of PEMDAS

10 - 64 + 13

- 54 + 13

- 41

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How do you simplify 4/5

Sladkaya [172]

4/5 is in its simplest form.

8 0

3 years ago

Read 2 more answers

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kondor19780726 [428]

Tree casts a shadow 30 feet long. A MHS student standing near the tree casts a shadow 9 feet long. The student is 6 feet tall. What is the height of the tree? Show all work

Answer:

Option D

The height of tree is 20 feet tall

Solution:

From given question,

Shadow of tree = 30 feet

Height of tree = ?

Height of student = 6 feet

Shadow of student = 9 feet

We have to find the height of tree

We can solve the sum by proportion

$\frac{\text{height of tree}}{\text{shadow of tree}} = \frac{\text{height of student}}{\text{shadow of tree}}$

This forms a proportion and we can solve the sum by cross multiplying

$\frac{\text{height of tree}}{30} = \frac{6}{9}\\\\\text{height of tree} = 30 \times \frac{6}{9} = 30 \times \frac{2}{3}\\\\\text{ height of tree } = 10 \times 2 = 20$

Thus height of tree is 20 feet tall

5 0

3 years ago

What is the equation of a line that is parallel to 4x+6y+5=0 and passes through the points (6,9)

OLga [1]

Step-by-step explanation:

Equation of given line is:

$4x+6y+5=0 \\ \therefore \: 6y = - 4x - 5 \\ \\ \therefore \: y = \frac{ - 4x - 5}{6} \\ \\ \therefore \: y = \frac{ - 4x}{6} - \frac{5}{6} \\ \\ \therefore \: y = - \frac{ 2}{3}x - \frac{5}{6}...(1) \\ equating \: eq \: (1) \: with \: y = mx + c, \:we \:\\ find : \\ slope \: of \: given \: line \: (m) = - \frac{ 2}{3} \\ \because \: required \: line \: is \: \parallel \: to \: given \: line \\ \therefore \: slope \: of \: required \: line \\ = slope \: of \: given \: line \: (m) = - \frac{ 2}{3} \\ \because \: required \: line \: passes \: through \: \\ point \: (6, \: 9) \\ \therefore \: \: equation \: of \: line \: in \: slope \: point \: \\ form \: is \: given \: as: \\ y-y_1=m(x-x_1) \\ \therefore \:y - 9 = - \frac{ 2}{3}(x - 6) \\ \therefore \:3(y - 9 )= - 2(x - 6) \\ \therefore \:3y - 27= - 2x + 12 \\ \therefore \:2x + 3y - 27 - 12 = 0 \\ \purple{ \boxed{\therefore \:2x + 3y - 39 = 0}} \\ is \: the \: equation \: of \: required \: line$