It is a bit tedious to write 6 equations, but it is a straightforward process to substitute the given point values into the form provided.
For segment ab. (x1, y1) = (1, 1); (x2, y2) = (3, 4).
... x = 1 + t(3-1)
... y = 1 + t(4-1)
ab = {x=1+2t, y=1+3t}
For segment bc. (x1, y1) = (3, 4); (x2, y2) = (1, 7).
... x = 3 + t(1-3)
... y = 4 + t(7-4)
bc = {x=3-2t, y=4+3t}
For segment ca. (x1, y1) = (1, 7); (x2, y2) = (1, 1).
... x = 1 + t(1-1)
... y = 7 + t(1-7)
ca = {x=1, y=7-6t}
10=1+9 1x9=9
=2+8 2x8=16
=3+7 3x7=21
=4+6 4x6=24
=5+5 5x5=25
↑ Left: the possible measurements of the two fences, Right: the possible areas
out of the areas calculated, 25 sq feet is the maximum. :)
Ans: 25 square feet
Answer:
m∠A = 59°
Step-by-step explanation:
Supplementary angles mean that, when the two are combined, their total measurement will equal 180°.
It is given that one of the angles is 121°. Subtract 121 from 180:
180 - 121 = 59
m∠A = 59°
~
Answer:
Step-by-step explanation:
(-2,0) and (8,0) are horizontally aligned, so the ellipse is horizontal.