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3 years ago

7

Aaron and his 2 friends found some money and split it even. Each received $5.00. How much did they find? a. $1000 b. $100 c. $15

d. $1500

1 answer:

hram777 [196]3 years ago

3 0

Answer:

15

Step-by-step explanation:

Aaron and his 2 friends = 3 people

Each received $5.00 = 3 people*5 each = 15 total

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During the summer months, science center tickets are 3 for $36.75 and zoo tickets are 4 for $51. How much will a group of 12 stu

Tatiana [17]

Answer:

$6

Step-by-step explanation:

Step 1:

36.75 × 4 = 147

Step 2:

51 × 3 = 153

Step 3:

153 - 147 = 6

The group of 12 students will save $6 by choosing the Science Center.

5 0

3 years ago

Read 2 more answers

Use technology and the given confidence level and sample data to find the confidence interval for the population mean mu . assum

attashe74 [19]

To solve for the confidence interval for the population mean mu, we can use the formula:

Confidence interval = x ± z * s / sqrt (n)

where x is the sample mean, s is the standard deviation, and n is the sample size

At 95% confidence level, the value of z is equivalent to:

z = 1.96

Therefore substituting the given values into the equation:

Confidence interval = 3 ± 1.96 * 5.8 / sqrt (51)

Confidence interval = 3 ± 1.59

Confidence interval = 1.41, 4.59

Therefore the population mean mu has an approximate range or confidence interval from 1.41 kg to 4.59 kg.

6 0

3 years ago

If a=2b^3 and b= -1/2c ^-2,express a in terms of c.

ElenaW [278]

Answer:

Part 1) $a=-\frac{1}{4c^6}$

Part 2) $a=-\frac{1}{4c^{-6}}$

Step-by-step explanation:

Part 1) we have

$a=2b^{3}$ ----> equation A

$b=-\frac{1}{2}c^{-2}$ ----> equation B

substitute equation B in equation A

$a=2(-\frac{1}{2}c^{-2})^{3}$

Applying property of exponents

$(x^{m})^{n}=x^{m*n}$

$x^{-m} =\frac{1}{x^{m}}$

$a=2(-\frac{1}{2}c^{-2})^{3}=2(-\frac{1}{2})^3(c^{-2})^{3}=2(-\frac{1}{8})(c^{-6})=-\frac{1}{4c^6}$

therefore

$a=-\frac{1}{4c^6}$

Part 2) we have

$a=2b^{3}$ ----> equation A

$b=-\frac{1}{2c^{-2}}=-\frac{c^{2}}{2}$ ----> equation B

substitute equation B in equation A

$a=2(-\frac{c^{2}}{2})^{3}$

Applying property of exponents

$(x^{m})^{n}=x^{m*n}$

$x^{-m} =\frac{1}{x^{m}}$

$a=2(-\frac{c^{2}}{2})^{3}=2(-\frac{c^{6}}{8})$

simplify

$a=-\frac{c^{6}}{4}$

therefore

$a=-\frac{1}{4c^{-6}}$

6 0

3 years ago

Ally ran 5 miles in 36 minutes. If Ally runs at the same rate, how long would it take her to run 1 mile?

Ne4ueva [31]

Answer:

7.2 Minutes

Step-by-step explanation:

Use Ratios

Miles : Minutes

5:36

Divide Both Sides By 5

1:7.2

It will Take Ally 7.2 Minutes To Run 1 Mile

5 0

3 years ago

Read 2 more answers

Please help the question is attached below

jasenka [17]

Step-by-step explanation:

a)

we have 400 people. that is 10/10 of the whole group.

7/10 of the whole group drink tea. that is

400 × 7/10 = 40 × 7 = 280

that leaves 3/10 of the whole group not drinking tea

400 × 3/10 = 40 × 3 = 120

from the 280 tea drinkers 20% drink at lay e cups of tea each day. that is

280 × 20/100 = 28 × 2 = 56

because 20 out of 100 is the meaning of 20%.

and the remaining 80% of the tea drinkers drink less then 3 cups each day.

280 × 80/100 = 28 × 8 = 224

b)

out of the 400 people 56 drink at least 3 cups of tea each day. that is

56/400 = 7/50

7 0

2 years ago