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ludmilkaskok [199]
3 years ago
12

Probability cards How to solve this, I don’t get it all all?

Mathematics
1 answer:
Ronch [10]3 years ago
3 0
There are 12 cards with different letters & patterns. The probability of randomly choosing [random card] is #[random card]/total cards.

Think of that as ratio as a %chance or probability of written as P(X). The question says to write the %chance as a fraction.

1) 2/12 = 1/6
2) 2/12 = 1/6
3) 0/12 = 0
4) 12/12 = 1
5) This is tricky. M & T would imply one card with both letters on it. 0/12 = 0
6) 4/12 = 1/3
7) 6/12 = 1/2
8) 5/12
9) 3/12 = 1/4
10) 8/12 = 2/3
11) 10/12 = 5/6
12) Odds = [favorable]:[unfavorable] = 5:7
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Suppose that a department contains 10 men and 12 women. How many ways are there to form a committee with six members if it must
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Answer:

The number of ways is 26,400 ways

Step-by-step explanation:

Given;

total number of men, M = 10

total number of women, W = 12

number of committees to be formed = 6

If there must be equal gender, then it must consist of 3 men and 3 women.

The \ number \ of \ ways = 10C_3 \times 12C_3\\\\The \ number \ of \ ways =\frac{10!}{3!7!} \times \frac{12!}{3!9!} \\\\T he \ number \ of \ ways  = 120 \times 220 = 26,400 \ ways

Therefore, the number of ways is 26,400 ways

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