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2 years ago

8 1/8 divided by 2 1/2

Mathematics

1 answer:

Alexxandr [17]2 years ago

5 0

$\huge\mathcal\pink{Answer}$

3 1/4 is the right answer

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A sporting goods store charges $30 for 12 cans of tennis balls and $45 for two boxes of golf balls. A coach orders100 cans of te

aliya0001 [1]

362.50 for tennis and golf balls.
To find the answer divide the dollar amount by how many cans or boxes each cost then multiply that answer by the total amount purchased.
Golf balls
45/2=22.50 each box
22.5*5=112.50 total
Tennis balls
30/12=2.50 each can
2.50*100 = 250.00
add the dollar amounts together
112.50+250.00 =362.50

3 0

3 years ago

a 5 digit number had the digits 0,5,7,9, and 0. to the nearest thousand, it rounds to 80000 what is the number? explain.

Murljashka [212]

The Number is 79500, since the nearest thousand for 79500 is 80000

7 0

3 years ago

Can any one help with this

natka813 [3]

Answer:

I know this isn't the whole answer but basicely just keep doing this to find the y-incercept

slope=-2.46

Hope This Helps!!!

4 0

2 years ago

Read 2 more answers

Can you please help?

Alborosie

Can’t help DDDD: bcoz link is a scam

7 0

3 years ago

Explain how to get that answer!!

ra1l [238]

We need to simplify $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$

First lets factor $\sqrt{14x^3}$

$\sqrt{14x^3}$ = $\sqrt{14} \sqrt{x^3}$
$\sqrt{14} = \sqrt{2} \sqrt{7}$ by applying the radical rule $\sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}$
$\sqrt{x^3} = x^{3/2}$ By applying the radical rule $\sqrt[n]{x^m} = x^{m/n}$

So
$\sqrt{14x^3}$ = $\sqrt{14} \sqrt{x^3}$ = $\sqrt{2} \sqrt{7}x^{3/2}$

Now let's factor $\sqrt{18x}$
By applying the radical rule $\sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}$ ,
$\sqrt{18x} = \sqrt{18} \sqrt{x}$
$\sqrt{18} = \sqrt{2} * 3$

So $\sqrt{18x}$ = $\sqrt{2}*3 \sqrt{x}$

So $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$ = $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3 \sqrt{x} }$

We know that $\sqrt[n]{x} = x^{1/n}$ so $\sqrt{x} = x^{1/2}$

We now have $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3 \sqrt{x}} = \frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3x^{1/2}}$

We know that $\frac{x^a}{x^b} = x^{a-b}$
So $\frac{x^{3/2}}{x^{1/2}} = x^{3/2 - 1/2} = x$

We now got $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3x^{1/2}} = \frac{ \sqrt{2} \sqrt{7} x }{ \sqrt{2}*3}
$

We can notice that the numerator and the denominator both got √2 in a multiplication, so we can simplify them, and we get:
$\frac{ \sqrt{2} \sqrt{7} x }{ \sqrt{2}*3} = \frac{ \sqrt{7}x }{3}$

All in All, we get $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$ = $\frac{ \sqrt{7}x }{3}$

Hope this helps! :D

6 0

3 years ago