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2 years ago

Please answer this question in two minutes

Mathematics

1 answer:

EastWind [94]2 years ago

7 0

Answer:

The other point is $R(19, 4)$

Step-by-step explanation:

$\frac{20+x}{2}=19.5\\\\\Rightarrow x = 19\\\\\frac{y+15}{2}=9.5\\\\\Rightarrow y=4$

Best Regards!

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Nikitich [7]

Answer:

Area of the shaded region = 23.33 in²

Step-by-step explanation:

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Area of the sector BCD = $\frac{60}{360}(\pi) (10^{2})$

= 52.36 in²

Area of equilateral triangle BCD = $\frac{\sqrt{3} }{4}(\text{Side})^2$

= $\frac{\sqrt{3} }{4}(10)^2$

= $25\sqrt{3}$ in²

= 43.30 in²

Area of the shaded portion in ΔBCD = 52.36 - 43.3

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Area of right triangle CAD = $\frac{1}{2}(\text{Base})(\text{Height})$

= $\frac{1}{2}(\text{AC})(\text{AD})$

= $\frac{1}{2}(\sqrt{50})(\sqrt{50})$

= 25 in²

Area of the shaded part in the ΔACD = 39.27 - 25

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Area of the shaded part of the figure = 9.06 + 14.27

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2 years ago

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2 years ago

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Step-by-step explanation:

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Find the difference quotient <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bf%28x%20%2B%20h%29%20-%20f%28x%29%7D%7Bh%7D" id="TexFor

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Answer:

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Step-by-step explanation:

Step 1: Define

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f(x) is just the normal function

Step 2: Find difference quotient

Substitute: $\frac{[-(x+h)^2-3(x+h)+1]-(-x^2-3x+1)}{h}$
Expand and Distribute: $\frac{[-(x^2+2hx+h^2)-3x-3h+1]+x^2+3x-1}{h}$
Distribute: $\frac{-x^2-2hx-h^2-3x-3h+1+x^2+3x-1}{h}$
Combine like terms: $\frac{-2hx-h^2-3h}{h}$
Factor out h: $\frac{h(-2x-h-3)}{h}$
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What is the slope of the way y-3=-4(x-5)

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