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Lesechka [4]
2 years ago
7

Simplify and find the reciprocal of 7/6 x -3/28

Mathematics
2 answers:
Basile [38]2 years ago
7 0

Answer:

Simplified it is -1 / 8

Reciprocal is 8/-1 or -8

Step-by-step explanation:

Multiply

7/6 x -3/28

= 7 x -3 / 6 x 28

= -21 / 168

Simplify

-21/21 = -1

168/21 = 8

-21/168 = -1/8

Find reciprocal

The reciprocal of a fraction is the numerator and denominator reversed

-1/8 > 8/-1

8/-1 is the same as -8

Hope this helps!

Snowcat [4.5K]2 years ago
6 0

Answer:

The product of \frac{7}{6} and -\frac{3}{28} is -\frac{1}{8}. The reciprocal is \frac{8}{-1}.

Step-by-step explanation:

We have to find the product of \frac{7}{6} and -\frac{3}{28} before we find the reciprocal.

Before we do this though, we need to review a few words and their definitions.

First, the reciprocal of a fraction is when the numerator becomes denominator and the denominator becomes numerator.

Now we're ready to solve \frac{7}{6} *-\frac{3}{28}:

Step 1: Use this rule: \frac{a}{b} *\frac{c}{d} =\frac{ac}{bd}.

\frac{7*-3}{6*28}

Step 2: Simplify 7 × - 3 to - 21.

\frac{-21}{6*28}

Step 3: Simplify 6 × 28 to 168.

\frac{-21}{168}

Step 4: Move the negative sign to the left.

-\frac{21}{168}

Step 5: Simplify \frac{21}{168} to \frac{1}{8}.

-\frac{1}{8}

Now that we've found the product, we now must find the reciprocal.

Now using what we know and the process to find the reciprocal.

We can use that knowledge to find it:

-\frac{1}{8} =\frac{8}{-1}

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Step-by-step explanation:

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2ᵃ = 5ᵇ = 10ⁿ.<br> Show that n = <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bab%7D%7Ba%20%2B%20b%7D%20" id="TexFormula1" titl
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There are two ways you can go about this: I'll explain both ways.
<span>
</span><span>Solution 1: Using logarithmic properties
</span>The first way is to use logarithmic properties.

We can take the natural logarithm to all three terms to utilise our exponents.

Hence, ln2ᵃ = ln5ᵇ = ln10ⁿ becomes:
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What's so neat about ln10 is that it's ln(5·2).
Using our logarithmic rule (log(ab) = log(a) + log(b),
we can rewrite it as aln2 = bln5 = n(ln2 + ln5)

Since it's equal (given to us), we can let it all equal to another variable "c".

So, c = aln2 = bln5 = n(ln2 + ln5) and the reason why we do this, is so that we may find ln2 and ln5 respectively.

c = aln2; ln2 = \frac{c}{a}
c = bln5; ln5 = \frac{c}{b}

Hence, c = n(ln2 + ln5) = n(\frac{c}{a} + \frac{c}{b})
Factorise c outside on the right hand side.

c = cn(\frac{1}{a} + \frac{1}{b})
1 = n(\frac{1}{a} + \frac{1}{b})
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\frac{1}{n} = \frac{a + b}{ab}
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<span>Solution 2: Using exponent rules
</span>In this solution, we'll be taking advantage of exponents.

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Then, 5 = c^{\frac{1}{b}}
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4 0
3 years ago
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