In degrees: 3π/4 radians = 135°
Angle of x=135° is in the 2nd Quadrant and has negative cos x values and positive sin x values.
cos 135° = cos ( 90° + 45°)= - sin 45° =
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sin 135° = sin ( 90° + 45° ) = cos 45° =
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. You can also see the graph in the attachment.
Answer:
Let the base be p
Hypotenuse = 2p +6
Perpendicular = 2p + 4
By Pythagoras theoram
(2p+6)^2 = (2p+4)^2 +p^2
=> 4p^2 +36 + 24p = 4p^2 + 16 +16p +p^2
=> 36+ 24p = p^2 + 16p + 16
=> p^2 - 8p - 20 = 0
=> p^2 - 10p +2p - 20 = 0
=> p(p-10) +2(p-10) = 0
=> (p-10)(p+2) = 0
p = 10 and - 2
Length can't be negative
So,
p = 10
Base = 10
Perpendicular = 24
Hypotenuse = 26
Answer:
simplify = 220x^2+2f−6x−14
factor = 2(110x^2+f−3x−7)
The answer isw c because when i first looked at it i was like its a then i soveled the problem out