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drek231 [11]
3 years ago
14

Please answer soon!

Mathematics
2 answers:
MA_775_DIABLO [31]3 years ago
7 0

Answer:

Answer is No.

Step-by-step explanation:

To construct a quadrilateral uniquely, five measurements are required.  A quadrilateral can be constructed uniquely if the lengths of its four sides and a diagonal are given or  if the lengths of its three sides and two diagonals are given.

Just given two angles we cannot construct a unique quadrilateral.  There may be an infinite number of quadrilaterals having atleast two right angles

Examples:

All squares with varying sides

All trapezoids with two right angles

All rectangles with different dimensions

and so on.

Answer is

No.

pav-90 [236]3 years ago
3 0
The figure is NOT unique.
 Imagine the following quadrilaterals:
 Rectangle
 Square
 We know that:
 Both quadrilaterals have at least two right angles.
 However, they are not unique because they depend on the lengths of their sides.
 Answer:
 
The figure described is not unique.
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Factor the trinomial:<br> -3y^2 + 7y + 20
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Answer:

here you goes hope it helps you

Step-by-step explanation:

1

Common factor

−

3

2

+

7

+

2

0

-3y^{2}+7y+20

−3y2+7y+20

−

1

(

3

2

−

7

−

2

0

)

-1(3y^{2}-7y-20)

−1(3y2−7y−20)

2

Use the sum-product pattern

−

1

(

3

2

−

7

−

2

0

)

-1(3y^{2}{\color{#c92786}{-7y}}-20)

−1(3y2−7y−20)

−

1

(

3

2

+

5

−

1

2

−

2

0

)

-1(3y^{2}+{\color{#c92786}{5y}}{\color{#c92786}{-12y}}-20)

−1(3y2+5y−12y−20)

3

Common factor from the two pairs

−

1

(

3

2

+

5

−

1

2

−

2

0

)

-1(3y^{2}+5y-12y-20)

−1(3y2+5y−12y−20)

−

1

(

(

3

+

5

)

−

4

(

3

+

5

)

)

-1(y(3y+5)-4(3y+5))

−1(y(3y+5)−4(3y+5))

4

Rewrite in factored form

Solution

−

1

(

−

4

)

(

3

+

5

)

6 0
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