mr.richard owns an orchard that has a rectangular fence. The orchard is 36 yards long and 18 yards wide. if he walks across the
diagonal length of the orchard how much distance would he cover
2 answers:
Answer: 40
Step-by-step explanation:
36^2 + 18^2 = x^2
Answer:
≈40.25 yards
Step-by-step explanation:
The diagnal length of the orchard is the hypotenuse of the triangal with side lengths of 36 and 18.
Therefore, to calculate that, set the hypotenuse as x.
36²+18²=x²
√1620≈ 40.25yards
You might be interested in
Answer:
427.09
Step-by-step explanation:
(2.75 x 107) + (1.23 x 108)
294.25 + 132.84 = 427.09
The ratio would be 8:20 or 8 to 20
(y^5-1)(y^5+8)............
Answer:
d= +3
Step-by-step explanation:
1st term = -19
2nd term = -16
d = 2nd - 1st
d= -16-(-19)
d = +3
Answer:
NRN
Step-by-step explanation: