All categories

3 years ago

At what price must I sell a motor car costing £2680 to make a gain of 5% on the cost? Please help

Mathematics

1 answer:

Papessa [141]3 years ago

3 0

So 2680 divided by 100 is 26.80 which is 1%, times 26.80 by 5 to get 5% = £134, £2680+134= £2814

You might be interested in

What is the value of the expression below when z = • 3?<br> 622 + 2z + 10

inn [45]

Answer:

632.6

Step-by-step explanation:

Z = .3 right? It looks weird on my screen

Anyway, if z is .3 than this is how to solve

First you plug in 0.3 where the z would go, making the expression 622 + 2(0.3) + 10. Then you solve! (below)

622 + 2(0.3) + 10.

622 + 0.6 + 10.

622 + 10 + 0.6

632 + 0.6

632.6

I hope this helped! If you have any questions, feel free to message me :)

3 0

2 years ago

9. Evaluate:

mrs_skeptik [129]

Answer:

Step-by-step explanation:

$a) 12\dfrac{1}{2}=\dfrac{25}{2}\\\\\dfrac{25}{2*100}*480= \dfrac{1}{2*4}*480 = 60 \ cm\\\\b) \dfrac{3}{4*100}*1200= 3*3 = 9 \ Rs.$

7 0

2 years ago

Read 2 more answers

Am I dealing with harmonic stuff (trig)?

pochemuha

You just need to solve for when $y=0$ :

$\dfrac{\cos8t-9\sin8t}4=0\implies\cos8t-9\sin8t=0$

$\implies\cos8t=9\sin8t$

$\implies\dfrac19=\dfrac{\sin8t}{\cos8t}=\tan8t$

$\implies8t=\tan^{-1}\dfrac19+n\pi$

$\implies t=\dfrac18\tan^{-1}\dfrac19+\dfrac{n\pi}8$

where $n$ is any integer. We only care about when $0\le t\le1$ , which happens for $n\in\{0,1,2\}$ .

$t=\dfrac18\tan^{-1}\dfrac19\approx0.01$

$t=\dfrac18\tan^{-1}\dfrac19+\dfrac\pi8\approx0.41$

$t=\dfrac18\tan^{-1}\dfrac19+\dfrac\pi4\approx0.80$

8 0

3 years ago

I’ll give brainliest please help

Angelina_Jolie [31]

Answer:

130

Step-by-step explanation:

91 is 70 percent of the price

70% of 130 is 130*0.7 = 91

5 0

3 years ago

Haii guys I need help ASAP pleasee

Evgen [1.6K]

Answer: 100

Step-by-step explanation: Part B is 100, you get that answer because you have ten put out the 1 and then the two is telling you to put 2 zeros .

3 0

3 years ago