Pemdas
in the parenthasees, we have 2*3 which is 6
then 6+21=27
now we have
(1/3)(27) times 3^2-5.6
exponents,, 3^2=9
(1/3)(27)(9)-5.6
multiply
81-5.6
minus
75.4
Ok, lets start with the top.
7/8 + (-2/3)
Thats equal to
7/8 - 2/3
The common denominator will be 24
21/24 - 16/24
Subtract
5/24
Now, to divide you multiply by the reciprocal, so
5/24 / 5/6
Becomes
5/24 * 6/5
Cross simplify and get your answer
1/4
y = 9ln(x)
<span>y' = 9x^-1 =9/x</span>
y'' = -9x^-2 =-9/x^2
curvature k = |y''| / (1 + (y')^2)^(3/2)
<span>= |-9/x^2| / (1 + (9/x)^2)^(3/2)
= (9/x^2) / (1 + 81/x^2)^(3/2)
= (9/x^2) / [(1/x^3) (x^2 + 81)^(3/2)]
= 9x(x^2 + 81)^(-3/2).
To maximize the curvature, </span>
we find where k' = 0. <span>
k' = 9 * (x^2 + 81)^(-3/2) + 9x * -3x(x^2 + 81)^(-5/2)
...= 9(x^2 + 81)^(-5/2) [(x^2 + 81) - 3x^2]
...= 9(81 - 2x^2)/(x^2 + 81)^(5/2)
Setting k' = 0 yields x = ±9/√2.
Since k' < 0 for x < -9/√2 and k' > 0 for x >
-9/√2 (and less than 9/√2),
we have a minimum at x = -9/√2.
Since k' > 0 for x < 9/√2 (and greater than 9/√2) and
k' < 0 for x > 9/√2,
we have a maximum at x = 9/√2. </span>
x=9/√2=6.36
<span>y=9 ln(x)=9ln(6.36)=16.66</span>
the
answer is
(x,y)=(6.36,16.66)
9514 1404 393
Answer:
see attached
Step-by-step explanation:
The base and height are perpendicular to each other. In each case, there is only one figure having a labeled h segment perpendicular to the labeled b.
Answer:
2
Step-by-step explanation:
20/2 = 10
4/2 = 2
