Answer:
Scrambled Eggs | 6 | 9 | 12 |
Hard Boiled Eggs | 2 | 4 | 6 |
Step-by-step explanation:
Scrambled Egg = Scrambled Egg + 3
Hard Boiled Egg = Hard Boiled Egg + 2
Since the degree of this polynomial is 5, there will be 5 possible zeros. To find the possible rational 0s, use the rational root theorem (p/q). P is the last, non x value, which here it is the four on the end. The q is the leading coefficient, which is also q. Next, find all of the factors of q and p, which since they are both 4, are ±1, ±2, and ±4. Next do all possible values of p/q, which are ±1, ±2, ±4, ±1/2, and ±1/4. These are all your possible rational zeros. complex 0s only come in pairs, so the maximum there can be is 4 complex zeros, meaning there is at least one rational, real 0. (i graphed it it is -1/2, so all others must be rational or imaginary)
129 divided by 5 is equal to 25 with a remainder of 4.
This means that she will need a total of 26 boxes, but only 25 of them will have 5 cupcakes in them. The last one will have 4 cupcakes.
x=1 f = 10(5.5)(1) = 55
x=2, f = 10(5.5)(2) = 110
110-55 = 55
2-1 =1
55/1 = 55
average rate of change = 55
Answer:
n can be a number less than 3
Step-by-step explanation:
Hope this helps!
