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BlackZzzverrR [31]
4 years ago
9

Measurement is ___________ when it yields the same values across repeated measurement of the same event.

Mathematics
1 answer:
Romashka [77]4 years ago
8 0

<span>The answer is reliable. A measure is assumed to have a high reliability if it yields parallel results under steady conditions. It is the characteristic of a set of test scores that relates to the quantity of accidental or random error from the measurement procedure that might be rooted in the scores. Marks that are highly reliable are precise, reproducible, and constant from one testing time to another. To be exact, if the testing method were to be repeated with a different group of test takers, fundamentally the same results would be gotten. </span>

You might be interested in
ΔPQR has angle measurements of 80°, 50°, and 50°. What kind of triangle is ΔPQR?
trasher [3.6K]

Answer:

Isosceles Triangle; Acute Triangle

Step-by-step explanation:

Review your definitions of the different types of triangles:

acute triangle- a triangle that has three acute (less than 90 degrees) angles

obtuse triangle- a triangle that has an obtuse (greater than 90 degrees) angle.

right triangle- a triangle that had one right (90 degrees) angles

isosceles triangle- a triangle with two congruent sides and one unique side and angle.

equilateral triangle-  a triangle with three congruent sides and three congruent angles.

scalene triangle- a triangle with no congruent sides and no congruent angles.

With these definitions, we can classify ΔPQR as an isosceles acute triangle.

8 0
3 years ago
This 1 seems really complicated
Fofino [41]
The solution to this system set is:  "x = 4" , "y = 0" ;  or write as:  [4, 0] .
________________________________________________________
Given: 
________________________________________________________
 y = - 4x + 16 ; 

 4y − x + 4 = 0 ;
________________________________________________________
"Solve the system using substitution" .
________________________________________________________
First, let us simplify the second equation given, to get rid of the "0" ; 

→  4y − x + 4 = 0 ; 

Subtract "4" from each side of the equation ; 

→  4y − x + 4 − 4 = 0 − 4 ;

→  4y − x = -4 ;
________________________________________________________
So, we can now rewrite the two (2) equations in the given system:
________________________________________________________
   
y = - 4x + 16 ;   ===> Refer to this as "Equation 1" ; 

4y − x =  -4 ;     ===> Refer to this as "Equation 2" ; 
________________________________________________________
Solve for "x" and "y" ;  using "substitution" :
________________________________________________________
We are given, as "Equation 1" ;

→  " y = - 4x + 16 " ;
_______________________________________________________
→  Plug in this value for [all of] the value[s] for "y" into {"Equation 2"} ;

       to solve for "x" ;   as follows:
_______________________________________________________
Note:  "Equation 2" :

     →  " 4y − x =  - 4 " ; 
_________________________________________________
Substitute the value for "y" {i.e., the value provided for "y";  in "Equation 1}" ;
for into the this [rewritten version of] "Equation 2" ;
→ and "rewrite the equation" ;

→   as follows:  
_________________________________________________

→   " 4 (-4x + 16) − x = -4 " ;
_________________________________________________
Note the "distributive property" of multiplication :
_________________________________________________

   a(b + c)  = ab + ac ;   AND: 

   a(b − c) = ab <span>− ac .
_________________________________________________
As such:

We have:  
</span>
→   " 4 (-4x + 16) − x = - 4 " ;
_________________________________________________
AND:

→    "4 (-4x + 16) "  =  (4* -4x) + (4 *16)  =  " -16x + 64 " ;
_________________________________________________
Now, we can write the entire equation:

→  " -16x + 64 − x = - 4 " ; 

Note:  " - 16x − x =  -16x − 1x = -17x " ; 

→  " -17x + 64 = - 4 " ;   Solve for "x" ; 

Subtract "64" from EACH SIDE of the equation:

→  " -17x + 64 − 64 = - 4 − 64 " ;   

to get:  

→  " -17x = -68 " ;

Divide EACH side of the equation by "-17" ; 
   to isolate "x" on one side of the equation; & to solve for "x" ; 

→  -17x / -17 = -68/ -17 ; 

to get:  

→  x = 4  ;
______________________________________
Now, Plug this value for "x" ; into "{Equation 1"} ; 

which is:  " y = -4x + 16" ; to solve for "y".
______________________________________

→  y = -4(4) + 16 ; 

        = -16 + 16 ; 

→ y = 0 .
_________________________________________________________
The solution to this system set is:  "x = 4" , "y = 0" ;  or write as:  [4, 0] .
_________________________________________________________
Now, let us check our answers—as directed in this very question itself ; 
_________________________________________________________
→  Given the TWO (2) originally given equations in the system of equation; as they were originally rewitten; 

→  Let us check;  

→  For EACH of these 2 (TWO) equations;  do these two equations hold true {i.e. do EACH SIDE of these equations have equal values on each side} ; when we "plug in" our obtained values of "4" (for "x") ; and "0" for "y" ??? ; 

→ Consider the first equation given in our problem, as originally written in the system of equations:

→  " y = - 4x + 16 " ;    

→ Substitute:  "4" for "x" and "0" for "y" ;  When done, are both sides equal?

→  "0 = ?  -4(4) + 16 " ?? ;   →  "0 = ? -16 + 16 ?? " ;  →  Yes!  ;

 {Actually, that is how we obtained our value for "y" initially.}.

→ Now, let us check the other equation given—as originally written in this very question:

→  " 4y − x + 4 = ?? 0 ??? " ;

→ Let us "plug in" our obtained values into the equation;

 {that is:  "4" for the "x-value" ; & "0" for the "y-value" ;  

→  to see if the "other side of the equation" {i.e., the "right-hand side"} holds true {i.e., in the case of this very equation—is equal to "0".}.

→    " 4(0)  −  4 + 4 = ? 0 ?? " ;

      →  " 0  −  4  + 4 = ? 0 ?? " ;

      →  " - 4  + 4 = ? 0 ?? " ;  Yes!
_____________________________________________________
→  As such, from "checking [our] answer (obtained values)" , we can be reasonably certain that our answer [obtained values] :
_____________________________________________________
→   "x = 4" and "y = 0" ;  or; write as:  [0, 4]  ;  are correct.
_____________________________________________________
Hope this lenghty explanation is of help!  Best wishes!
_____________________________________________________
7 0
3 years ago
Is 2,12 4,24 6,36 8,48 10,60 proportional
Elena L [17]

Answer:

Yes

Step-by-step explanation:

12 divided by 2 = 6, 24 divided by 4 = 6, 36 divded by 6 = 6, 48 divded by 8 = 6, 60 divided by 10 = 6.  

All answers have 6 so yes it is proportional.

4 0
3 years ago
I need help!! Please help me
Zinaida [17]

Answer:

y= 6

Step-by-step explanation:

A horizontal line means y = something  ( the x value will change, but y remains the same)

In this case, the y value is 6

y= 6

8 0
3 years ago
Find the Surface Area:<br><br> A) 200 in^2<br> B) 300 in^2<br> C) 500 in^2<br> D) 400 in^2
rosijanka [135]

Answer: B

Step-by-step explanation:

3 0
2 years ago
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