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3 years ago

13

Please help Leslie has a watering can that holds 3 liters of water.She uses 250 milliliters of water on each other plants how ma

ny plants can she waterrr?

1 answer:

vredina [299]3 years ago

4 0

Answer:

12

Step-by-step explanation:

1 liter=1000 ml

3 liter=3×1000=3000 ml

number of plants=3000/250=12

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PLEASE ANSWER I WILL GIVE 30 POINTS!

Bingel [31]

Answer:

So the correct answer is"none of the above".

Step-by-step explanation:

z+(z+6)=z+z+6=2z+6. \\ \\ (z+z)+(z+6)=z+z+z+6=3z+6. \\ \\ (z+6)+6=z+12 \\ \\

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3 years ago

I need help for this table option

Angelina_Jolie [31]

Answer:

4.3 g

Step-by-step explanation:

An outlier is a data point that strays far from the average of the group.

The other data points are all close to 3.

See how 4.3 is way farther from 3 than all the rest?

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2 years ago

Alex invests his money in an account paying 2% interest compounded semiannually. What is the effective annual yield on this acco

Travka [436]

Answer: 2.01%.

Step-by-step explanation:

Suppose Alex invests $1 into the account for one year. The formula is A=P0⋅(1+rk)N⋅k with P0=$1. We know that r=0.02 and k=2 compounding periods per year. Now, N=1 year. Substituting the values we have A=$1⋅(1+0.022)2=$1.0201. Now, to calculate the effective annual yield, we will use the formula rEFF=A−P0P0. rEFF=1.0201−11=0.0201 or 2.01%. When rounded to two decimals, rEFF=2.01%. However, do not include the % in your answer.

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2 years ago

How to do this type of questions

neonofarm [45]

The pattern is +5 +5 -1 +6 So the answer should be (B) 30,29,35

3 0

3 years ago

The cost of 3 subs and 7 cookies is $18.75. Five subs and 21 cookies cost

bazaltina [42]

One sub costs $4.5 and one cookie costs $0.75 or 75 cents

Step-by-step explanation:

Let s be the cost of one sub

and

c be the cost of one cookie

Then according to given statements

"The cost of 3 subs and 7 cookies is $18.75"

$3s+7c = 18.75\ \ \ Eqn\ 1$

"Five subs and 21 cookies cost $38.25"

$5s+21c = 38.25\ \ \ \ Eqn\ 2$

Multiplying eqn 1 by 3

$9s+21c = 56.25\ \ \ Eqn\ 3$

Subtracting Eqn 2 from Eqn 3

$9s+21c- (5s+21c) = 56.25-38.25\\9s+21c-5s-21c = 18\\4s = 18$

Dividing both sides by 4

$\frac{4s}{4} =\frac{18}{4}\\s = 4.5$

Putting s=4.5 in Eqn 1

$3s+7c = 18.75\\3(4.5)+7c = 18.75\\13.5+7c = 18.75\\7c = 18.75-13.5\\7c =5.25$

Dividing both sides by 7

$\frac{7c}{7}=\frac{5.25}{7}\\c = 0.75$

So,

One sub costs $4.5 and one cookie costs $0.75 or 75 cents

Keywords: Linear Equations, Variables

Learn more about linear equations at:

#LearnwithBrainly

8 0

3 years ago