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adoni [48]
2 years ago
8

Can you please help me? as much as you can is greatly appreciated <333 pt 1

Mathematics
1 answer:
zhuklara [117]2 years ago
4 0

Answer:

<em>11) </em><em>80°</em>

<em>12) </em><em>80°</em>

<em>13) </em><em>80°</em>

<em>14) </em><em>40°</em>

<em>15) </em><em>60°</em>

<em>16) </em><em>120°</em>

<em>17) </em><em>180°</em>

<em>18) </em><em>100°</em>

<em>19) </em><em>120°</em>

<em>20) </em><em>280°</em>

Step-by-step explanation:

This will take awhile, so I will just give you the theorems I used to determine my answer.

11) Supplementary angles theorem

12) Central Angles/Arcs Theorem

13) Vertical Angles Theorem

14) Central Angles/Arcs Theorem

15) Vertical Angles Theorem (The vertical angle minus 40 would equal 60)

16) Supplementary Angles Theorem (Supplementary to 100 degrees)

17) Central Angles/Arc Theorem

18) Vertical Angles & Central Angles/Arc Theorem

19) Angle Addition Postulate, somewhat

20) Angle Addition Postulate

<em>Have a nice day, fam. This problem really worked my brain. Spread The Love.</em>

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love history [14]

Answer:

3x+y=18

3xy=18

xy= 18/3

xy=6

5 0
2 years ago
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find the probability of being delt 5 clubs and 3 cards with one of each remaining suit in 8 card poker
kumpel [21]

Answer: 0.003757(approx).

Step-by-step explanation:

Total number of combinations of selecting r things out of n things is given by:-

^nC_r=\dfrac{n!}{r!(n-r)!}

Total cards in a deck = 52

Total number of ways of choosing 8 cards out of 52 = ^{52}C_8

Total number of ways to choose 5 clubs and 3 cards with one of each remaining suit = ^{13}C_5\times^{13}C_1\times^{13}C_1\times^{13}C_1  [since 1 suit has 13 cards]

The required probability = =\dfrac{^{13}C_5\times^{13}C_1\times^{13}C_1\times^{13}C_1}{^{52}C_8}

=\dfrac{\dfrac{13!}{5!8!}\times13\times13\times13}{\dfrac{52!}{8!44!}}\\\\=\dfrac{24167}{6431950}\\\\\approx0.003757

Hence, the required probability is 0.003757 (approx).

5 0
2 years ago
Is the point (−7,1) a solution to the inequality y&lt;0.5x+9?<br> yes or no
pshichka [43]
(-7,1) is a solution to the inequality y<0.5x+9
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3 years ago
What is the degree of the polynomial?<br><br> 4x3+3x2−9x+7
PolarNik [594]

Answer:

3

Step-by-step explanation:

The highest degree amount or exponet amount is the power of a equation.

3 is the highest exponet so it is 3.

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Use the Fundamental Theorem for Line Integrals to find Z C y cos(xy)dx + (x cos(xy) − zeyz)dy − yeyzdz, where C is the curve giv
Harrizon [31]

Answer:

The Line integral is π/2.

Step-by-step explanation:

We have to find a funtion f such that its gradient is (ycos(xy), x(cos(xy)-ze^(yz), -ye^(yz)). In other words:

f_x = ycos(xy)

f_y = xcos(xy) - ze^{yz}

f_z = -ye^{yz}

we can find the value of f using integration over each separate, variable. For example, if we integrate ycos(x,y) over the x variable (assuming y and z as constants), we should obtain any function like f plus a function h(y,z). We will use the substitution method. We call u(x) = xy. The derivate of u (in respect to x) is y, hence

\int{ycos(xy)} \, dx = \int cos(u) \, du = sen(u) + C = sen(xy) + C(y,z)  

(Remember that c is treated like a constant just for the x-variable).

This means that f(x,y,z) = sen(x,y)+C(y,z). The derivate of f respect to the y-variable is xcos(xy) + d/dy (C(y,z)) = xcos(x,y) - ye^{yz}. Then, the derivate of C respect to y is -ze^{yz}. To obtain C, we can integrate that expression over the y-variable using again the substitution method, this time calling u(y) = yz, and du = zdy.

\int {-ye^{yz}} \, dy = \int {-e^{u} \, dy} = -e^u +K = -e^{yz} + K(z)

Where, again, the constant of integration depends on Z.

As a result,

f(x,y,z) = cos(xy) - e^{yz} + K(z)

if we derivate f over z, we obtain

f_z(x,y,z) = -ye^{yz} + d/dz K(z)

That should be equal to -ye^(yz), hence the derivate of K(z) is 0 and, as a consecuence, K can be any constant. We can take K = 0. We obtain, therefore, that f(x,y,z) = cos(xy) - e^(yz)

The endpoints of the curve are r(0) = (0,0,1) and r(1) = (1,π/2,0). FOr the Fundamental Theorem for Line integrals, the integral of the gradient of f over C is f(c(1)) - f(c(0)) = f((0,0,1)) - f((1,π/2,0)) = (cos(0)-0e^(0))-(cos(π/2)-π/2e⁰) = 0-(-π/2) = π/2.

3 0
3 years ago
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