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lana66690 [7]
3 years ago
8

Find the surface area of the triangular pyramid. The side lengths of the base are equal.

Mathematics
1 answer:
Sliva [168]3 years ago
3 0

Answer:

<h2>133.5 cm²</h2>

Step-by-step explanation:

We have

three triangles with the base <em>b = 10cm</em> and the height <em>h₁ = 6cm</em>

one triangle with the base <em>b = 10cm</em> and the height <em>h₂ = 8.7cm</em>.

The formula of an area of a triangle:

A=\dfrac{b\cdot h}{2}

<em>b</em><em> - base</em>

<em>h</em><em> - height</em>

Substitute:

A_1=\dfrac{(10)(6)}{2}=\dfrac{60}{2}=30\ cm^2

A_2=\dfrac{(10)(8.7)}{2}=\dfrac{87}{2}=43.5\ cm^2

S.A.=3A_1+A_2\\\\S.A.=3(30)+43.5=90+43.5=133.5\ cm^2

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Convert the complex number z = 4 - 10i from rectangular form to polar form.​
mrs_skeptik [129]

ANSWER

r = 2 \sqrt{29} ( \cos(292 \degree)  + \sin(292 \degree))

EXPLANATION

The polar form of a complex number ,

z = x + yi

is given by:

z = r( \cos( \theta)  + i \sin( \theta) )

where

r =  \sqrt{ {x}^{2} +  {y}^{2}  }

The given complex number is:

z = 4 - 10i

r =  \sqrt{ {4}^{2}  +  {( - 10)}^{2} }

r =  \sqrt{16  + 100}

r =  \sqrt{116}  = 2 \sqrt{29}

And

\theta=  \tan^{ - 1}(\frac{ y}{x} )

\theta=  \tan^{ - 1}(\frac{  - 10}{4} )

\theta=  292 \degree

Hence the polar form is :

r = 2 \sqrt{29} ( \cos(292 \degree)  + \sin(292 \degree))

6 0
3 years ago
What is the mode for 2103 and 623m
lions [1.4K]

there is no mode

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3 0
3 years ago
the sum of the perimeter of two squares is 40cm while the sum of the area is 58cm². Find length the side of the square.
tia_tia [17]

a,\ b-the\ length\ of\ sides\\\\(1)\qquad4a+4b=40\qquad\text{divide both sides by 4}\\\\a+b=10\to a=10-b\\\\(2)\qquad a^2+b^2=58\\\\\text{Substitute}\ (1)\ \text{to}\ (2):\\\\(10-b)^2+b^2=58\qquad\text{Use}\ (x-y)^2=x^2-2xy+y^2\\\\10^2-2(10)(b)+b^2+b^2=58\\\\100-20b+2b^2=58\qquad\text{subtract 58 from both sides}\\\\42-20b+2b^2=0\\\\2b^2-20b+42=0\qquad\text{divide both sides by 2}\\\\b^2-10b+21=0\\\\b^2-7b-3b+21=0\\\\b(b-7)-3(b-7)=0\\\\(b-7)(b-3)=0\iff b-7=0\ \vee\ b-3=0\\\\\boxed{b=7\ \vee\ b=3}

\text{Put the values of b to }\ (1):\\\\for\ b=7\to a=10-7=3\\\\for\ b=3\to a=10-3=7\\\\Answer:\ \boxed{7cm\ and\ 3cm.}

8 0
4 years ago
The point (-2,3) is the solution to a system of two linear equations. Which of the following can be one of the
Fynjy0 [20]

Answer:

We conclude that The point (-2, 3) satisfies the equation y = -x+1.

Hence, option B i.e. y = -x+1 is one of the equations of a system of two linear equations.

Step-by-step explanation:

Given

  • The point (-2, 3)

<u>Checking option A</u>

Given the equation

y = 3x-2

substitute x = -2 and y = 3

3 = 3(-2) - 2

3 = -6 - 2

3 = -8

FALSE!

L.H.S ≠ R.H.S

Thus,

The point (-2, 3) does not satisfy the equation y = 3x-2.

<u>Checking option B</u>

Given the equation

y = -x+1

substitute x = -2 and y = 3

3 = -(-2)+1

3 = 2+1

3 = 3

TRUE!

L.H.S = R.H.S

Thus,

The point (-2, 3) satisfies the equation y = -x+1.

<u>Checking option C</u>

Given the equation

y=x-1

substitute x = -2 and y = 3

3 = -2-1

3 = -3

FALSE!

L.H.S ≠ R.H.S

Thus,

The point (-2, 3) does not satisfy the equation y=x-1.

<u>Checking option D</u>

Given the equation

y=2x+3

substitute x = -2 and y = 3

3 = 2(-2)+3

3 = -4+3

3 = -1

FALSE!

L.H.S ≠ R.H.S

Thus,

The point (-2, 3) does not satisfy the equation y=2x+3.

Conclusion:

Thus, we conclude that The point (-2, 3) satisfies the equation y = -x+1.

Hence, option B i.e. y = -x+1 is one of the equations of a system of two linear equations.

4 0
3 years ago
The angles of a triangle are 2x , 3x ,and 4x degrees . find the value of x
BigorU [14]

Answer:

24

Step-by-step explanation:

2;3;4;x

2x 3x =6x

six is equal to the x an. four

4 0
4 years ago
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