Answer:
See below.
Step-by-step explanation:
By definition the median of the triangle bisects the base of the isosceles triangle.
We need to prove that the 2 triangles formed by the median are congruent.
If the 2 triangles are ABD and ACD where BD is the median and < ABC is the angle from which BD is drawn.
BD = BD ( the common side)
AD = DC ( because BD is the median).
AB = AC ( because ABC is an isosceles triangle).
So Triangles ABD and ACD are congruent by SSS.
Therefore m < ABD = m < CBD, so BD is the bisector of < ABC.
To prove BD is also the altitude:
Triangles ABD and CBD are congruent as we have just proven. Therefore the
of measure of the base angle ABD = m < CBD . Also they are adjacent angles ( on the same line) so they add up to 180.
Therefore angles ABD and CBD are both right angles and BD is the altitude of triangle ABC.
I believe the answer is C!
The discriminant is b²-4ac
when the discriminant is 0, there is only one solution.
Answer:
Step-by-step explanation:
1) 4x -3
x = -7 ;
4x - 3 = 4*(-7) - 3 = - 28 - 3 = -31
x = 14 ;
4x - 3 = 4*14 - 3 = 56 - 3 = 53
x = 0
4x - 3 = 0 - 3 = -3
2) 6 -3x
x = -7 ;
6 - 3x = 6 - 3*(-7) = 6 + 21 = 27
x = 14
6 - 3x = 6 - 3*14 = 6 - 42 = -36
x = 0
6 - 3x = 6 - 0 = 6

4)
