Question

The equation y+6=1/3(x-9) is written in point-slope form. What is the equation written in slope-intercept form?

Answer 1

Answer: $y=\dfrac{1}{3}x-9$

Step-by-step explanation:

The equation of a line in slope -intercept form is written as :-

$y=mx+c$

The given equation : $y+6=\dfrac{1}{3}(x-9)$

To write the given equation in slope - intercept form , we need to first solve the right -hand sides in the equation.

$y+6=\dfrac{1}{3}(x-9)\\\\\Rightarrow\ [tex]y+6=\dfrac{1}{3}x-3\\\\\Rightarrow\ y=\dfrac{1}{3}x-3-6\\\\\Rightarrow\ y=\dfrac{1}{3}x-9$

Hence, the equation written in slope-intercept form :  $y=\dfrac{1}{3}x-9$

Answer 2

y+6=1/3(x-9)

Moved all terms from left to right that doesn't contain y

Y=-6 +1/3x-3

Simplify

Y=1/3x-9

Your answer is c.