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3 years ago

What is the answer of the rectangular prism? 3 1/3 times 1 2/5

Mathematics

1 answer:

Sunny_sXe [5.5K]3 years ago

6 0

Answer:

Step-by-step explanation:

3 1\3 = 1

1 2\5 = 2/5 ..........................

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Find the intercept(s) of the following equation.<br> y = 2x^2-8

grin007 [14]

X intercepts- (2,0) and (-2,0)
y intercept- (0,-8)

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3 years ago

ANSWER THIS HURRY I WILL GIVE BRAINLIST 20 POINTS

sleet_krkn [62]

Answer:

table f is the one that is proportional

Step-by-step explanation:

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3 years ago

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30 dogs to 20 cats lowest fraction

Romashka [77]

Answer:

Answer : 3/2

Step-by-step explanation:

30/20= 3/2

it is because we don't want the zero so that we can take it off.

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3 years ago

P = $14,300

Arte-miy333 [17]

Answer:

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Step-by-step explanation:

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3 years ago

If 30,000 cm2 of material is available to make a box with a square base and an open top, what is the largest possible volume (in

Cloud [144]

Answer:

The largest possible volume of the box is 2000000 cubic meters.

Step-by-step explanation:

The volume ( $V$ ), in cubic centimeters, and surface area ( $A_{s}$ ), in square centimeters, of the box with a square base are described below:

$A_{s} = l^{2}+h\cdot l$ (1)

$V = l^{2}\cdot h$ (2)

Where:

$l$ - Side length of the base, in centimeters.

$h$ - Height of the box, in centimeters.

By (2), we clear $h$ within the formula:

$h = \frac{V}{l^{2}}$

And we apply in (1) and simplify the resulting expression:

$A_{s} = l^{2}+ \frac{V}{l}$

$A_{s}\cdot l = l^{3}+V$

$V = A_{s}\cdot l -l^{3}$ (3)

Then, we find the first and second derivatives of this expression:

$V' = A_{s}-3\cdot l^{2}$ (4)

$V'' = -6\cdot l$ (5)

If $V' = 0$ and $A_{s} = 30000\,cm^{2}$ , then we find the critical value of the side length of the base is:

$30000-3\cdot l^{2} = 0$

$3\cdot l^{2} = 30000$

$l = 100\,cm$

Then, we evaluate this result in the expression of the second derivative:

$V'' = -600$

By Second Derivative Test, we conclude that critical value leads to an absolute maximum. The maximum possible volume of the box is:

$V = 30000\cdot l - l^{3}$

$V = 2000000\,cm^{3}$

The largest possible volume of the box is 2000000 cubic meters.

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2 years ago