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riadik2000 [5.3K]
3 years ago
11

Triangle ABC has coordinates A(-2,0), B(0,2) and C(-4, 3). It is reflected across the line y = 2/5x - 2. About where is B’ locat

ed? What is the equation of the line that joins CC’? (2 points)
Mathematics
1 answer:
vredina [299]3 years ago
8 0

Answer:

B' is at (2.76,-4.9)

Equation of CC' is 11.38x+4.55y= -31.86

or at its slope-intercept form:

y= (-11.38x - 31.86)/4.55

Step-by-step explanation:

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Can someone check questions?
Soloha48 [4]
1
The first one is correct. 

2
A hexagon has the weird property of having the radius and the side being of exactly the same length

The formula is A = 3 * sqrt(3) * a^2 / 2
where a = the side  or radius
A = 3 * sqrt(3) * 5^2 / 2
A = 3 * sqrt(3) * 25 / 2
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A <<<< Answer (the first one is the answer.) 


C
This one seems so much more entailed. Do you know what the cos law is? That's what I will use to find c.

c^2 = a^2 + b^2 - 2*ab* cos(C)
C = 33 degrees
a = 2.75 miles
b = 1.32 miles

c^2 = 2.75^2 + 1.32^2 - 2 * 2.75 * 1.32 * cos(33)
c^2 = 9.3049 - 6.0887
c^2 = 3.2162
c = sqrt(3.2162) = 1.7934 

Now you have to use this result to get the area. You have to use Heron's formula.

A = sqrt(s * (s - a) * (s - b) * (s - c) )
s = 1/2 the perimeter
s = 1/2 (2.75 + 1.32 + 1.7934)
s = 1/2(5.8634)
s = 2.9317
I'll finish this in the comments. I have to leave for a bit.

6 0
4 years ago
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73. you subtract 89 and 16 and that gives you your answer which is*** 73***
7 0
3 years ago
Read 2 more answers
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