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Ipatiy [6.2K]
3 years ago
5

Find the real root of the equation x3 + x2 - 1 = 0 byusing iteration method.​

Mathematics
1 answer:
Yanka [14]3 years ago
7 0

Answer:

i cant help that much but u can try using photomath

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Suppose two bicyclists start at the same location.
DerKrebs [107]

Answer:

Step-by-step explanation:

See attachment.

If both cyclists travel for the same time and speed, they will have travelled the same distance.  Since one is headed north and the other east, we can see that the distance between them in one hour is the hypotenuse of a right triangle.  Each leg has distance x.  We can say x^2 + x^2 = (3\sqrt{2})^2

2x^2 =1 8

x^2 = 9

x = 3

They both rode 3 miles.

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3 years ago
A tennis team has won 15 out of 20 matches they played this season. How many additional matches must the team win in a row to ra
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You need to win 30 matches in a row to raise its winning percentage to 90%
7 0
4 years ago
Considering only the values of β for which sinβtanβsecβcotβ is defined, which of the following expressions is equivalent to sinβ
-Dominant- [34]

Answer:

\tan(\beta)

Step-by-step explanation:

For many of these identities, it is helpful to convert everything to sine and cosine, see what cancels, and then work to build out to something.  If you have options that you're building toward, aim toward one of them.

{\tan(\theta)}={\dfrac{\sin(\theta)}{\cos(\theta)}    and   {\sec(\theta)}={\dfrac{1}{\cos(\theta)}

Recall the following reciprocal identity:

\cot(\theta)=\dfrac{1}{\tan(\theta)}=\dfrac{1}{ \left ( \dfrac{\sin(\theta)}{\cos(\theta)} \right )} =\dfrac{\cos(\theta)}{\sin(\theta)}

So, the original expression can be written in terms of only sines and cosines:

\sin(\beta)\tan(\beta)\sec(\beta)\cot(\beta)

\sin(\beta) * \dfrac{\sin(\beta) }{\cos(\beta) } * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) } {\sin(\beta) }

\sin(\beta) * \dfrac{\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} {\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}

\sin(\beta) *\dfrac{1 }{\cos(\beta) }

\dfrac{\sin(\beta)}{\cos(\beta) }

Working toward one of the answers provided, this is the tangent function.


The one caveat is that the original expression also was undefined for values of beta that caused the sine function to be zero, whereas this simplified function is only undefined for values of beta where the cosine is equal to zero.  However, the questions states that we are only considering values for which the original expression is defined, so, excluding those values of beta, the original expression is equivalent to \tan(\beta).

8 0
2 years ago
A bouquet of 40 flowers is made up of roses, carnations, and daisies. The bouquet is 45% roses and 15% carnations. How many of t
max2010maxim [7]

Answer:

18 flowers are roses (so sorry this got to me so late!)

Step-by-step explanation:

find 45% of 40

4 0
3 years ago
Can anyone help me with 2 and 3 (different one)
Aloiza [94]
Fraction would be 30/100 and decinal would be .30 and ratio would be 30/100
5 0
3 years ago
Read 2 more answers
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