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alina1380 [7]
3 years ago
12

In ΔABC, m∠ACB = 90°, CD ⊥ AB and m∠ACD = 45°. Find: AC, if CD = 6√2 in.

Mathematics
1 answer:
klio [65]3 years ago
5 0

Answer:

AC = 12 units.

Step-by-step explanation:

Δ ACD is right-angled. ( as CD ⊥ AB).

cos 45° = CD / AC = 6√2 / AC

AC = 6√2 / cos 45°

AC = 6√2 / 1 /√2

= 6√2 *√2

= 6 * 2

= 12   (answer)

HOPE THIS HELPED ;3

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miss Akunina [59]

Answer:

∠2

Step-by-step explanation:

A supplementary angle is a 180° angle formed by two angles. ∠3 and ∠2 form a straight line / 180° angle.

5 0
3 years ago
What is the modulus of |9+40i|?
Talja [164]

Answer:

41

Step-by-step explanation:

We know that complex numbers are a combination of real and imaginary numbers

Real part is x and imaginary part y is multiplied by i, square root of -1

Modulus of x+iy = \sqrt{x^2+y^2}

Here instead of x and y are given 9 and 40

i.e. 9+40i

Hence to find modulus we square the coefficients add them and then find square root

|9+49i| =\sqrt{9^2+40^2} =\sqrt{1681}

By long division method we find that

|9+40i| =41


6 0
3 years ago
Read 2 more answers
Answer this thanks!!!!
kirill115 [55]

Answer:

B

Step-by-step explanation:

$65×6%=$3.90

$3.90+$65=$68.90

m I right

4 0
3 years ago
Read 2 more answers
2(x-3)-8< -4 I need a explanation and the answer please.
tresset_1 [31]

Answer:

The solution to the inequality is:

x

The number line solution graph is also attached below.

Step-by-step explanation:

Given the inequality

2(x-3)-8< -4

Add 8 to both sides

2\left(x-3\right)-8+8

2\left(x-3\right)

Divide both sides by 2

\frac{2\left(x-3\right)}{2}

x-3

Add 3 to both sides

x-3+3

x

Thus, the solution to the inequality is:

x

The number line solution graph is also attached below.

6 0
3 years ago
B. The school prom committee sold presale tickets for
Ivan

Answer:

218 students purchased tickets at the dance.

Step-by-step explanation:

Let,

x be the number of presale tickets

y be the number of tickets sold at the dance

According to given statement;

x+y=334      Eqn 1

18x+24y=7320    Eqn 2

Multiplying Eqn 1 by 18

18(x+y=334)

18x+18y=6012      Eqn 3

Subtracting Eqn 3 from Eqn 2

(18x+24y)-(18x+18y)=7320-6012

18x+24y-18x-18y=1308

6y=1308

\frac{6y}{6}=\frac{1308}{6}\\y=218

Therefore,

218 students purchased tickets at the dance.

5 0
3 years ago
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