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Anna35 [415]
3 years ago
9

Which type of triangle has special proportions?

Mathematics
1 answer:
pochemuha3 years ago
7 0
The correct answer will greatly depend on the side angle of the given object. Due to the insinuation theory if an object is greater than 11 or x>11 and is equally likely even but different than the third odd length then the equation of 2x(ml) *11^2 can be created. Cheers
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What is the length of segment VS?<br> O 3 units<br> 11 units<br> 13 units<br> O 15 units
sergeinik [125]

Answer:

VS = 11

Step-by-step explanation:

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5 0
3 years ago
After the movie premiere 99 out of 130 people surveyed said they liked the movie. What is the experimental probability that the
Margaret [11]
Out of the 130 people surveyed, 99 people said they liked the movie. So to figure out the probability that the next person likes the movie, you divide 99 from 130. 
The answer is approximately 76%.
6 0
3 years ago
Need help in algebra quick
vlabodo [156]

Answer: 6 is the y intercept

Step-by-step explanation:

5 0
3 years ago
where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤
marusya05 [52]

THIS IS THE COMPLETE QUESTION BELOW

The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.

Answer

$168.27

Step by step Explanation

Given p=90000/400+3x

With the limits of 40 to 50

Then we need the integral in the form below to find the average price

1/(g-d)∫ⁿₐf(x)dx

Where n= 40 and a= 50, then if we substitute p and the limits then we integrate

1/(50-40)∫⁵⁰₄₀(90000/400+3x)

1/10∫⁵⁰₄₀(90000/400+3x)

If we perform some factorization we have

90000/(10)(3)∫3dx/(400+3x)

3000[ln400+3x]₄₀⁵⁰

Then let substitute the upper and lower limits we have

3000[ln400+3(50)]-ln[400+3(40]

30000[ln550-ln520]

3000[6.3099×6.254]

3000[0.056]

=168.27

the average price p on the interval 40 ≤ x ≤ 50 is

=$168.27

8 0
3 years ago
Please help !! Picture provided !!!
adelina 88 [10]
Method One
Your calculator might be able to do this. Mine does it like this.
6
nCr
2  
= 
15

Method 2
You could simply set up 6C2

This gives you
\frac{n!}{(n- r)! r!} =  \frac{6!}{(6 - 2)!2!} =  \frac{6!}{4! 2!} =  \frac{6*5}{2*1} = 15

Method Three
You only have to do this a couple of times to see how the cancellation works.

\frac{6!}{4!2!} =  \frac{6*5*\st{4*3*2*1}}{4*3*2*1 * 2*1}
After all the cancellation takes place you have
6*5/2 = 15
7 0
3 years ago
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