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meriva
3 years ago
11

(tanx+sinx)(1-cosx)=sin^2xtanx

Mathematics
1 answer:
exis [7]3 years ago
6 0
<span> [(sinx/cosx)+sinx](1-cosx) 
[(sinx+sinx.cosx/cosx)](1-cosx) 
[ sinx(1-cosx)+sinxcosx(1-cosx)]/cosx 
sinx-sinxcosx+sinxcosx-sinx cos^2 x/cosx 

sinx-sinx cos^2 x/cosx 
sinx(1-cos^2 x)/cosx
(1-cos^2x)sinx/cosx 
sin(squared)x.tanx.......R.H.S</span>
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