Answer:
NORMDIST(RAND(),50,5)
Step-by-step explanation:
NORMDIST(RAND(),50,5) returns the random value from a normal distribution. The second space is meant for Mean and the third space is meant for standard deviation.
Answer:
P(4.7≤x≤5.3)≈0.6827≈68.27%
Step-by-step explanation:
Notice that 4.7 is 1 standard deviation below the mean (μ) and 5.3 is 1 standard deviation above the mean. Thus, by the Empirical Rule, ±1σ represents about 68.27% of the data in a normal distribution, meaning that P(4.7≤x≤5.3)≈0.6827
I have never heard of a five-yard law so i have no clue but maybe a 5 yard lawn is possible
X = 3, y = 4
or if u want coordinates: (3,4)