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lozanna [386]
3 years ago
14

Mhanifa please help! This is due soon

Mathematics
1 answer:
Zanzabum3 years ago
7 0

Answer:

By using the Pythagorean theorem, the sides form a right triangle:

36^2 + 15^2 = 39^2

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A tank with a capacity of 1000 L is full of a mixture of water and chlorine with a concentration of 0.02 g of chlorine per liter
faltersainse [42]

At the start, the tank contains

(0.02 g/L) * (1000 L) = 20 g

of chlorine. Let <em>c</em> (<em>t</em> ) denote the amount of chlorine (in grams) in the tank at time <em>t </em>.

Pure water is pumped into the tank, so no chlorine is flowing into it, but is flowing out at a rate of

(<em>c</em> (<em>t</em> )/(1000 + (10 - 25)<em>t</em> ) g/L) * (25 L/s) = 5<em>c</em> (<em>t</em> ) /(200 - 3<em>t</em> ) g/s

In case it's unclear why this is the case:

The amount of liquid in the tank at the start is 1000 L. If water is pumped in at a rate of 10 L/s, then after <em>t</em> s there will be (1000 + 10<em>t</em> ) L of liquid in the tank. But we're also removing 25 L from the tank per second, so there is a net "gain" of 10 - 25 = -15 L of liquid each second. So the volume of liquid in the tank at time <em>t</em> is (1000 - 15<em>t </em>) L. Then the concentration of chlorine per unit volume is <em>c</em> (<em>t</em> ) divided by this volume.

So the amount of chlorine in the tank changes according to

\dfrac{\mathrm dc(t)}{\mathrm dt}=-\dfrac{5c(t)}{200-3t}

which is a linear equation. Move the non-derivative term to the left, then multiply both sides by the integrating factor 1/(200 - 5<em>t</em> )^(5/3), then integrate both sides to solve for <em>c</em> (<em>t</em> ):

\dfrac{\mathrm dc(t)}{\mathrm dt}+\dfrac{5c(t)}{200-3t}=0

\dfrac1{(200-3t)^{5/3}}\dfrac{\mathrm dc(t)}{\mathrm dt}+\dfrac{5c(t)}{(200-3t)^{8/3}}=0

\dfrac{\mathrm d}{\mathrm dt}\left[\dfrac{c(t)}{(200-3t)^{5/3}}\right]=0

\dfrac{c(t)}{(200-3t)^{5/3}}=C

c(t)=C(200-3t)^{5/3}

There are 20 g of chlorine at the start, so <em>c</em> (0) = 20. Use this to solve for <em>C</em> :

20=C(200)^{5/3}\implies C=\dfrac1{200\cdot5^{1/3}}

\implies\boxed{c(t)=\dfrac1{200}\sqrt[3]{\dfrac{(200-3t)^5}5}}

7 0
3 years ago
4’1” - 1’ 10” whats is
cluponka [151]

Since inches are out of 12 this would be

4 ft - 1 ft = 3 ft

3' 1" - 1 " = 3 '

3 feet is also 2 ft and 12 inches

2' 12" - 9 " = 2' 3"

So the answer is 2 feet and 3 inches

Hope this helps

-GoldenWolfX

7 0
4 years ago
please help me solve these 1, 2, 7 and 8 questions!! I will also be giving out brainlest and 30 points to you if you get it righ
dusya [7]
1. Yes it shows proportional relationship because they go by 5.
2. okay.. so your answer choices are 3) 2, 4) 10, 5) -2, and 6) 8. I'M GONNA GUESS. it's going to be #3. 
3. Okay so $100- 30 - 10 = $60 That means that each hat cost $6 dollars and he bought 10 of them so 10 times 6 equals 60. 
4. they cost 4.50 because she bought ten of them so if you multiply 4.50 by ten you get 45 and she had 5 left over. 

Hope this helped! 

:)

Please tell me which ones were wrong and which ones were right!
5 0
4 years ago
What is the domain of the cubic function f(x)=10x^3 +18x
sweet [91]

ANSWER

(-∞,+∞)

EXPLANATION

The given polynomial function is:

f(x)=10x^3 +18x

The domain refers to all values of x that make the function defined.

Polynomial functions are defined for all real values of x

The domain is the set of all real numbers.

This is written in symbolic representation as

(-∞,+∞)

8 0
3 years ago
Peter wants to test an assumption on the number of trees that tested positive for a particular infestation. He decides to focus
LUCKY_DIMON [66]

Answer:

H0 : P ≤ 0.12

H1 : P > 0.12

Step-by-step explanation:

12% = 12/ 100 = 0.12

Given the population proportion, P = 0.12

The claim is the alternative hypothesis, H1 ; which is to test if more than 12% of trees have been infested.

Hence, the alternative hypothesis will be ;

H1 : P > 0.12

The null hypothesis which is the initial truth is always the opposite of the alternative hypothesis, Therefore, we write our null as ;

The null hypothesis ; H0 : P ≤ 0.12

Therefore, we have :

H0 : P ≤ 0.12

H1 : P > 0.12

4 0
3 years ago
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