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Artist 52 [7]
4 years ago
15

Passing through (-6,-1) and parallel to y=-2/3x +1

Mathematics
1 answer:
zheka24 [161]4 years ago
5 0

Hello!

To find the line parallel to the line y = -2/3x + 1 and passing through the point (-6, -1), we will need to know that if two lines are parallel, then their slopes are equivalent to each other.

Since we are given the slope, we need to find the y-intercept of the line. We can find the y-intercept by substituting the point (-6, -1) into a new equation with the slope of m = -2/3. Remember that slope-intercept form is y = mx + b.

y = -2/3x + b (substitute the ordered pair)

-1 = -2/3(-6) + b

-1 = 4 + b (subtract 4 from both sides)

-5 = b

Therefore, the equation of the line passing through the point (-6, -1) and parallel to y = -2/3x + 1 is y = -2/3x - 5.

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C

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x²-14x-49=0

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2 years ago
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6 0
3 years ago
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I dont understand this question. Also if anyone is on geometry byu part two let me know and we can work together !
damaskus [11]

Answer:

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Step-by-step explanation:

The problem says that m∠TRS = 120º. The total number of degrees in a circle is 360º. 120º is a third of 360º. Therefore, we can prove that the shaded sector is a third of the circle.

The problem then says that the area of the shaded sector is 25π and we have to calculate the area of the entire circle. Since we already know that the shaded sector is a third of the circle, we can simply multiply 25π by 3 in order to calculate the area of t he entire circle.

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4 0
3 years ago
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