We want to determine the equation in point slope form for the line that is perpendicular to the given line and passing through the point (5.6) .
The equation and the point is;
We know that for two lines to be perpendicular, the product of their slopes should be -1.
Therefore, the slope of the perpendicular should be;
The second condition is that the line must pass through the point (5,6) , to do thid, we write the equation of the line in point slope form which is;
Inserting all values, we have,
That is the final answer.
Answer:
it false because its |-6|=6 and |6|= 6
hopefully its helpful and correct
have a great day
Answer:
1.) 2x-y=-7 --> y=2x + 7
2.) 5x+3y=12 --> y= -5/3x + 4
3.) x-y=1 --> y= x- 1
4.) x-3y=-15 --> y=1/3x + 5
5.) 8x-10y=20 --> y=4/5x - 2
6.) 14x+6y=36 --> y=-7/3x+6
Step-by-step explanation:
Hope this helped.
This would be 56 - p because 'fewer' indicates subtraction.
Answer:
y=4x-5.
Step-by-step explanation:
slop-interception form of the required line is y=kx+b, where k - slop, b - intercept;
1) to find value of k:
if the required line is parallel to the given line, then slop of the given line = slop of the required line, it means k=4 and the required line is y=4x+b;
2) to find the value of 'b':
if to substitute the given coordinates into the equation of the given line, then:
15=4*5+b, b= -5.
3) finally, y=4x-5
