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Alekssandra [29.7K]

3 years ago

13

Question and Answers below in photo!! Please answer! Will mark BRAINLIEST! ⬇⬇⬇⬇⬇⬇⬇

1 answer:

Gemiola [76]3 years ago

4 0

Answer:

B. 72 yd^3

Step-by-step explanation:

First we find the area of the base, which is the triangle.

Area = (1/2)(base)(height)

A = 1/2(3)(8) = 1/2(24) = 12

Multiply that base area by the height (6)

12 x 6 = 72

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12.20x=372.10<br> Pls write exactly how to do it not just answer

ANEK [815]

To find x, you divide both sides of the equation by 12.20. This would look like this:
12.20x/12.20 =372.10/12.20 . Then, the answer you get is 30.5, so. X=30.5

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3 years ago

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Multiply 2/3 x 4 . Write in simplest form. Does the first factor increase or decrease?

jolli1 [7]

2 2×4 8
--- × 4 = ------- = ------
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the first factor increase

hope helped

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4 years ago

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This extreme value problem has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the ex

pashok25 [27]

Answer with Step-by-step explanation:

We are given that

$f(x,y,z)=10x+10y+3z$

$g(x,y,z)=5x^2+5y^2+3z^2=43$

We have to find the extreme values of the function.

$f_x(x,y,z)=10,f_y(x,y,z)=10,f_z(x,y,z)=3$

$g_x(x,y,z)=10x,g_y(x,y,z)=10y,g_z(x,y,z)=6z$

$\Delta f(x,y,z)=\lambda \Delta g(x,y,z)$

Therefore,

$10=\lambda 10x\implies x=\frac{1}{\lambda}$

$10=10y\lambda\implies y=\frac{1}{\lambda}$

$3=6z\lambda$

$z=\frac{1}{2\lambda}$

Substitute the values in g(x)

Then, we get

$\frac{5}{\lambda^2}+\frac{5}{\lambda^2}+\frac{3}{4\lambda^2}=43$

$\frac{20+20+3}{4\lambda^2}=43$

$\frac{43}{4\lambda^2}=43$

$\lambda^2=\frac{43}{4\times 43}$

$\lambda=\pm\frac{1}{2}$

When $\lambda=\frac{1}{2}$ then,

$x=2,y=2,z=1$

When $\lambda=-\frac{1}{2}$

Then, $x=-2,y=-2,z=-1$

$f(2,2,1)=10+10+3=23$

$f(-2,-2,-1)=-10-10-3=-23$

Hence, maximum value of f(x,y,z) is 23 at (2,2,1) and minimum value of f(x,y,z) is -23 at (-2,-2 ,-1).

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4 years ago

Order these fractions from smallest to lowest<br> 1<img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5Cfrac%7B7%7D%7B12

chubhunter [2.5K]

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Step-by-step explanation<em>: </em>

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2 years ago

Sometimes integers are encoded by using four-digit binary expansions to represent each decimal digit. this produces the binary c

wolverine [178]

<span>You're wasting a whole lot of possible 'space' in that encoding solution, but the answer is 4n. </span>

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4 years ago