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Maslowich
3 years ago
10

A continuous function graph shows unbroken lines or curves or part of a line or curve.

Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
3 0

This is very true for a function that is continuous.

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Kate collected a sample of monthly rents and recorded the following numbers:
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C) will not effected (the most frequent is still 600$)
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Sue bought two shirts on sale. She would have to pay $20.00 for each shirt, but she got them for 25% off. The two shirts also ha
andrezito [222]
$20×.25=$5
$20-$5=$15
$15×.15=$2.25
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$17.25 is your answer
4 0
3 years ago
Find the net change in the value of the function between the given inputs. h(t) = t2 + 2; from −5 to 8
pashok25 [27]

Answer:

39

Step-by-step explanation:

Given the function :

h(t) = t² + 2

From t = 5 to t = 8

when, t = 5

h(5) = 5² + 2

h(5) = 25 + 2

h(t) at t = 5 ; equals 27

when, t = 8

h(5) = 8² + 2

h(5) = 64 + 2

h(t) at t = 8 ; equals 66

Net Change :

h(8). - h(5)

66 - 27 = 39

3 0
3 years ago
Doris made a list of all the whole number from 1 to 100 how many times did she write the digit 2
STALIN [3.7K]
She wrote it 22 times
3 0
3 years ago
For what value of c is the function defined below continuous on (-\infty,\infty)?
kozerog [31]
f(x)= \left \{ {{x^2-c^2,x \ \textless \  4} \atop {cx+20},x \geq 4} \right


It's clear that for x not equal to 4 this function is continuous. So the only question is what happens at 4.
<span>A function, f, is continuous at x = 4 if 
</span><span>\lim_{x \rightarrow 4} \  f(x) = f(4)

</span><span>In notation we write respectively
</span>\lim_{x \rightarrow 4-} f(x) \ \ \ \text{ and } \ \ \ \lim_{x \rightarrow 4+} f(x)

Now the second of these is easy, because for x > 4, f(x) = cx + 20. Hence limit as x --> 4+ (i.e., from above, from the right) of f(x) is just <span>4c + 20.
</span>
On the other hand, for x < 4, f(x) = x^2 - c^2. Hence 
\lim_{x \rightarrow 4-} f(x) = \lim_{x \rightarrow 4-} (x^2 - c^2) = 16 - c^2

Thus these two limits, the one from above and below are equal if and only if
 4c + 20 = 16 - c²<span> 
 Or in other words, the limit as x --> 4 of f(x) exists if and only if
 4c + 20 = 16 - c</span>²

c^2+4c+4=0&#10;\\(c+2)^2=0&#10;\\c=-2

That is to say, if c = -2, f(x) is continuous at x = 4. 

Because f is continuous for all over values of x, it now follows that f is continuous for all real nubmers (-\infty, +\infty)

4 0
3 years ago
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