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yan [13]
3 years ago
8

Use the product property for radicals to simplify the following radical expressions as much as possible. Square root of 54

Mathematics
1 answer:
Svetllana [295]3 years ago
8 0

Answer:

3*sqrt(6)

Step-by-step explanation:

1. sqrt(54) = sqrt(3^2*6)

2. factor our 3^2

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Please help I'm so close to being done and I don't know how to do this!!! Pls give answer but show how to do it!!!
cestrela7 [59]

Answer:

  • 8y + 16

Step-by-step explanation:

The shaded area is the difference of the large and small squares.

<u>Area of large square:</u>

  • A(l) =  (y + 4)²

<u>Area of small square:</u>

  • A(s) = y²

<u>Shaded area:</u>

  • A = A(l) - A(s)
  • A = (y + 4)² - y² = y² + 8y + 16 - y² = 8y + 16

4 0
2 years ago
D=.5*a*t^2 - solving for a<img src="https://tex.z-dn.net/?f=d%3D.5%2Aa%2At%5E2" id="TexFormula1" title="d=.5*a*t^2" alt="d=.5*a*
Leviafan [203]

Answer:

\displaystyle a=\frac{d}{.5*t^2}

Step-by-step explanation:

<u>Equation Solving</u>

We are given the equation:

d=.5*a*t^2

It's required to solve it for a.

Swap sides to have the letter on the left side:

.5*a*t^2=d

Divide by .5*t^2:

\mathbf{\displaystyle a=\frac{d}{.5*t^2}}

7 0
3 years ago
Help Me Please ! This is so confusing .‍♀️
Savatey [412]

Answer: -4

Step-by-step explanation:

3-9=-6

-6*5=-30

-30-1=-31

6*-31=-186

-186+2=-184

8-2=6

6*7=42

42+4=46.

-184/46=-4

6 0
3 years ago
Mr. Park pays $1000 per month in rent. Before depositing his paycheck, his checking account balance was $359.47. After the depos
IrinaVladis [17]

Answer:

Mr Park has enough money to pay his rent.

Step-by-step explanation:

The amount of the monthly rent paid  = $1000

The account balance after depositing the paycheck = $1441.33

Now, to pay the rent,account should have more than the rent money $1000

Also, $1441.33  >  $1000

⇒ The amount in the bank after depositing the paycheck   >  The rent to be paid

Hence, Mr Park has enough money to pay his rent.

6 0
3 years ago
What is the radius of the circle given the equation x2 - 6x + y2 + 10y + 18 = 0?
arlik [135]
The\ equation\ of\ a\ circle:(x-a)^2+(y-b)^2=r^2\\\\(a;\ b)-a\ coordinates\ of\ the\ center\\r-a\ radius

x^2-6x+y^2+10y+18=0\\\\x^2-2x\cdot3+y^2+2y\cdot5=-18\\\\x^2-2x\cdot3+3^2+y^2+2y\cdot5+5^2=-18+3^2+5^2\ \ \ |use\ (a\pm b)^2=a^2\pm2ab+b^2\\\\(x-3)^2+(y+5)^2=-18+9+25\\\\(x-3)^2+(y+5)^2=16\\\\therefore\\\\Answer:\boxed{r=\sqrt{16}=4}
7 0
3 years ago
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