Answer:
Since the above triangle is Iscocleles we can make our equation-
5x - 8 = 2x + 7
5x - 2x = 8 + 7
3x = 15
x = 5
Hope it helps
Answer:
l=0.1401P\\
w =0.2801P
where P = perimeter
Step-by-step explanation:
Given that a window is in the form of a rectangle surmounted by a semicircle.
Perimeter of window =2l+\pid/2+w

Or 
To allow maximum light we must have maximum area
Area = area of rectangle + area of semi circle where rectangle width = diameter of semi circle


Hence we get maximum area when i derivative is 0
i.e. 

Dimensions can be

A) 8 possibilities
BBB
GBB, BGB, BBG
BGG, GBG, GGB
GGG
B) 0, 1, or 2 boys not 3
7/8
C) 2 or 3 girls
4/8=1/2
D) same sex
2/8=1/4
Answer: 8x³ + 12x² - 16x - 16
<u>Step-by-step explanation:</u>
(4x² - 2x - 4)(2x + 4)
= (2x + 4)(4x² - 2x - 4)
= 2x(4x² - 2x - 4) + 4(4x² - 2x - 4)
= 8x³ - 4x² - 8x + 16x² - 8x - 16
= 8x³ + (-4x² + 16x²) + (-8x - 8x) - 16
= 8x³ + 12x² - 16x - 16