Answer:
Step-by-step explanation:
The question is incomplete. Here is the complete question.
In a square ABCD, if AB = (3x-8) and BC = (x+12), find the value of x. Also, find the length of each side of the square.
Note that all sides of a square are equal. Hence AB = BC for the square ABCD.
Given AB = (3x-8) and BC = (x+12), then AB = BC
3x-8 = x+12
collect like terms;
3x-x = 12+8
2x = 20
x = 20/2
x = 10
Substitute x = 10 into any of the side. Using side AB
AB = 3x-8
AB = 3(10)-8
AB = 30-8
AB = 22
BC = x+12
BC = 10+12
BC = 22
<em>Hence x = 10 and the length of each side is 22</em>
8 and 25 thats the answer
Answer:
112
Step-by-step explanation:
7 x 3=21
125-34=91
91 + 21=112
Problem # 1
3w-10=4w+5
(3w-10) + (10-4w) = (4w+5) + (10-4w)
(3w-10) + (-4w+10) = (4w+5) + (-4w +10)
3w-10-4w+10 = 4w +5 -4w +10
3w-4w=15
-w=15
w= -15 (w is negative 15)
problem #2.
6-2t > 18
6-2t-6 > 18-6
-2t > 12
(-1) (-2t) > 12 (-1)
2t > -12
next divide by 2
2t/2 > -12/2
t > -6 (t is greater then negative 6)
Answer:
b) -2/5
Step-by-step explanation:
b is -2/5 because its negative and goes down at a rate of 0.4 or 2/5
a , ummmm IDK that, sorry
Brainliest, crown to me