Answer:
x = 5
y = 1
Step-by-step explanation:
So move 2y from the second equation to the other side of the equals sign
2x +3y = 13
x = 3 + 2y
From here substitute X into the first equation
2(3 + 2y) + 3y = 13
Distribute
6 + 4y +3y = 13
Combine like terms and solve for y
7y = 7
y = 1
insert result into the original equation.
x-2(1) = 3
x - 2 = 3
x = 5
insert into other equation to check work
2(5) + 3(1) = 13
10 + 3 = 13 correct
Answer:
Required ordered pair is (0,0) for system of equation
Step-by-step explanation:
The given system of equation is
A). 
B). 
On simplifying the equation A
Take log on both side,
(12x) (log9) = (3y) (log9)
4x=y
To find the solution of the system of the equation :
Replacing value of y=4x in equation B,
We get,
x=0 and x=0.829
Since, 0.829 is not integer number
Only solution of equations is x=0
For the value of y
Replace value x in y=4x=0
Thus, Required ordered pair is (0,0)
Answer:
48 sweets
Step-by-step explanation:
5:2:4
Sarah: 5
Natasha:2
Richard:4
To find out how many sweets Richard got, we need to use 60 as the lcm. Since, we have a definite constant of 60 we need to divide it by the presiding ratio.
60/5 = 12
That means for a ratio of 1, everyone in the group recieves 12.
Now, we plug it in for each of the members.
5x = Sarah
2x = Natasha
4x = Richard
Sarah = 60 sweets
Natasha = 24 sweets
Richard = 48 sweets
24 thirds because if you split all the kilograms 8(3) =24
