Answer:
Number of calls expected in next week by manager = 7940
Average Number of calls that call center agent will attend in an hour =7 calls
It is also given that, Call center remain open for 10 hours 5 days a week.
Also, it is given that, full time agents work 40 hours a week but are only on call for 35 hours per week ,Part time agents work 20 hours a week but are only on calls 17 hours per week .
⇒Number of hours worked by full time agents × Number of calls attended in an hour × Number of full time agents + Number of hours worked by Part time agents × Number of calls attended in an hour × Number of Part time agents ≤ 7940
⇒35 × 7×Number of full time agents +17 × 7 ×Number of Part time agents ≤ 7940
Option A
⇒35×15×7+17×7×15
= 3675+1785
= 5460
Option B
⇒35 ×7×20+17×7×7
=4900 +833
= 5733
Option C
⇒35×20×7 +17×20×7
=4900+2380
=7280
Option D
⇒25 × 35×7+17×7×5
=6125 +595
=6720
Option E
⇒28×35×7+17×7×10
=6860+1190
=8050
Option E, ⇒ 28 full time agents and 10 part time agents , is best to meet the scheduling needs is most appropriate, that is nearer to 7940 calls.
A.125
Because to get from 5 to 25 you need to multiply by 5 so 25 times five equals 125
Answer:
Step-by-step explanation:
The equation of a hyperbola is 
/9 - 
/4 = 1
What are the steps to Hyperbola equation ?
To find the equation of hyperbola, the following steps must be taken. You need to identify;
- The coordinate of the center
- The coordinate of the vertices
- The coordinate of the foci
The general equation of a hyperbola can be expressed as
/
- /
= 1
From the graph, we have the following parameters
a = 3
= 
= 9
b = 2
= 
= 4
The equation of a hyperbola can be expressed as
/9 - /4 = 1
The vertices = V(+/-a,0) = (+/-3,0)
The center = C(0,0)
The focus = F(+/-C, 0)
Where 
= +
C = 
C = 
Focus = F(+/- , 0)
The general equation for asymptote = +/- b/a X
= +/-2/3X
Therefore, the equation of a hyperbola can be expressed as
/9 - /4 = 1
Learn more about hyperbola here: brainly.com/question/3405939
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