Simultaneous Equations
2u + b = $110
4u + 3b = $268
(x2) 4u + 2b = $220
(x1) 4u + 3b = $268
<em />If both the matching coefficients are the same, we subtract equation 2 from equation 1
2b - 3b = -b
$220 - $268 = $-48
-b = -$48
b = $48
If you want to find out what a unicycle costs...
Substitute b = $48 into the first equation
2u + $48 = $110
Balance the equation, whatever happens on one side, happens on the other.
2u + $48 (-$48) = $110 (-$48)
2u = $62
2u(/2) = $62(/2)
u = $31
Answer:
the required answer is

Step-by-step explanation:
here's the solution : -
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<span>Simplifying
4(y + -3) = 6(y + 2)
Reorder the terms:
4(-3 + y) = 6(y + 2)
(-3 * 4 + y * 4) = 6(y + 2)
(-12 + 4y) = 6(y + 2)
Reorder the terms:
-12 + 4y = 6(2 + y)
-12 + 4y = (2 * 6 + y * 6)
-12 + 4y = (12 + 6y)
Solving
-12 + 4y = 12 + 6y
Solving for variable 'y'.
Move all terms containing y to the left, all other terms to the right.
Add '-6y' to each side of the equation.
-12 + 4y + -6y = 12 + 6y + -6y
Combine like terms: 4y + -6y = -2y
-12 + -2y = 12 + 6y + -6y
Combine like terms: 6y + -6y = 0
-12 + -2y = 12 + 0
-12 + -2y = 12
Add '12' to each side of the equation.
-12 + 12 + -2y = 12 + 12
Combine like terms: -12 + 12 = 0
0 + -2y = 12 + 12
-2y = 12 + 12
Combine like terms: 12 + 12 = 24
-2y = 24
Divide each side by '-2'.
y = -12
Simplifying
y = -12</span>
We have been given the expression

We have the exponent rule

Using this rule, we have

Now, using the fact that
, we get
![x^{\frac{9}{7}}= \sqrt[7]{x^9}\\ \\ x^{\frac{9}{7}}=\sqrt[7]{x^7\times x^2}\\ \\ x^{\frac{9}{7}}=x\sqrt[7]{x^2}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7B9%7D%7B7%7D%7D%3D%20%5Csqrt%5B7%5D%7Bx%5E9%7D%5C%5C%0A%5C%5C%0Ax%5E%7B%5Cfrac%7B9%7D%7B7%7D%7D%3D%5Csqrt%5B7%5D%7Bx%5E7%5Ctimes%20x%5E2%7D%5C%5C%0A%5C%5C%0Ax%5E%7B%5Cfrac%7B9%7D%7B7%7D%7D%3Dx%5Csqrt%5B7%5D%7Bx%5E2%7D)
D is the correct option.
D = 2r => 12.6 = 2*r => r=6.3
A = π*r^2 = (3.14) * (6.3)^2 = (3.14)*(39.69) = 124.6266 which is approximately 124.63
Hope this helps!