Using the table, we will see that the function is:
t(l) = 3*l
<h3>
How to write the function?</h3>
Here we only have a table to work with, so we need to use that.
In the table, we can see the pairs:
- t(1) = 3
- t(2) = 6
- t(3) = 9
- t(4) = 12
So, in each new level, we just add 3 more toothpicks. Even more, we can see that the number of toothpicks is 3 times the value of l (the level) for all the cases in the table. So this is a linear function.
From that we can conclude that the function will be:
t(l) = 3*l
If you want to learn more about linear functions, you can read:
brainly.com/question/4025726
Answer:
![Proj_{v}U=\frac{u\cdot v}{\left\lVert v \right\rVert^2}v=\frac{-1-5+4}{\left(\sqrt{(-1)^2+(1)^2+(1)^2}\right)^2}(-1,1,1)=\left(\frac{2}{3},-\frac{2}{3},-\frac{2}{3}\right).](https://tex.z-dn.net/?f=Proj_%7Bv%7DU%3D%5Cfrac%7Bu%5Ccdot%20v%7D%7B%5Cleft%5ClVert%20v%20%5Cright%5CrVert%5E2%7Dv%3D%5Cfrac%7B-1-5%2B4%7D%7B%5Cleft%28%5Csqrt%7B%28-1%29%5E2%2B%281%29%5E2%2B%281%29%5E2%7D%5Cright%29%5E2%7D%28-1%2C1%2C1%29%3D%5Cleft%28%5Cfrac%7B2%7D%7B3%7D%2C-%5Cfrac%7B2%7D%7B3%7D%2C-%5Cfrac%7B2%7D%7B3%7D%5Cright%29.)
Step-by-step explanation:
The orthogonal projection of U along V is a vector defined by
such that
. From here we obtain that ![\lambda=\frac{u\cdot v}{\left\lVert v \right\rVert ^{2}}.](https://tex.z-dn.net/?f=%5Clambda%3D%5Cfrac%7Bu%5Ccdot%20v%7D%7B%5Cleft%5ClVert%20v%20%5Cright%5CrVert%20%5E%7B2%7D%7D.)
A. 2 • 1 = 2
b. 2 • 2 - 2 • 1 = 2
d. 2 - 1 = 1
The correct answer is D.