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dolphi86 [110]
3 years ago
7

Jordan uses a linear equation to model the data in a table. Which reasoning might Jordan have used in the decision to model the

data with a linear equation?
The products of corresponding x- and y-values are equal.
The ratios of consecutive y-values are equal for evenly spaced x-values.
The change in y-values is not constant, but the change is constant for evenly spaced x-values.
The change in y-values is constant for evenly spaced x-values.
Mathematics
2 answers:
Anton [14]3 years ago
5 0

ANSWER:

the answer is D.

Mariulka [41]3 years ago
3 0
The last option:The change in y-values is constant for evenly spaced x-values.

Remember that the change in y divided by the change in x is the slope of a line and it is constant.



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Answer:

3 miles.

Step-by-step explanation:

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Solve the system by substitution. 4x+3y=5x=4y+6Options: A. The solution is ____B. There are infinitely many solutions. C. There
zvonat [6]

So we have the following system of equations:

\begin{gathered} 4x+3y=5 \\ x=4y+6 \end{gathered}

We need to solve it by substitution. This means that we have to take the expression for x given by the second equation and replace x with it in the first equation:

\begin{gathered} 4x+3y=5 \\ 4\cdot(4y+6)+3y=5 \\ 16y+24+3y=5 \\ 16y+3y=5-24 \\ 19y=-19 \\ y=-\frac{19}{19}=-1 \end{gathered}

So y=-1. If we use this value in the second equation:

\begin{gathered} x=4y+6 \\ x=4\cdot(-1)+6 \\ x=-4+6 \\ x=2 \end{gathered}

So we have x=2 and y=-1 which means that there's one solution. Then the correct answer is A and the solution is (2,-1).

5 0
1 year ago
Which symbol makes a true statement? –2.75 ? –3 A. = B. > C.
Iteru [2.4K]
<span>–2.75 >  –3

answer is </span><span>B. ></span>
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3 years ago
Please solve this question!!​
GaryK [48]

Answer:  (i) 1/221     (ii) 11/221      (iii) 95/663        (iv) 1/663

<u>Step-by-step explanation:</u>

(i) A deck of cards contains 4 Kings out of 52 total cards

1st draw: 4 Kings out of 52 total cards → 4/52 = 1/13

2nd draw: 3 remaining Kings out of 51 total remaining cards  →  3/51 = 1/17

  <u>1st Draw </u>                   <u>2nd Draw </u>                  <u>Outcome</u>         <u>Probability</u>

 King: P(K) = 1/13        King: P(K₂/K₁) = 1/17     King, King       (1/13) x (1/17) = 1/221

*************************************************************************************************

(ii) A deck of cards contains 4 Jacks, 4 Queens, & 4 Kings out of 52 total cards

1st draw: 12 Face cards out of 52 total cards → 12/52 = 3/13

2nd draw: 11 remaining Face cards out of 51 total remaining cards  →  11/51

<u>1st Draw </u>                 <u>2nd Draw </u>                  <u>Outcome</u>       <u>Probability</u>

 Face: P(F) = 3/13    Face: P(F₂/F₁) = 11/51   Face,Face     (3/13) x (11/51) = 11/221

*************************************************************************************************

(iiI) A deck of cards contains 26 black cards out of 52 total cards but there are 2 black Jacks, 2 black Queens, and 2 black Kings.

1st draw: 20 Black (not Face) cards out of 52 total cards → 20/52 = 5/13

2nd draw: 19 remaining Black (not Face) cards out of 51 total remaining cards  →  19/51

  <u>1st Draw </u>                 <u>2nd Draw </u>                       <u>Outcome</u>   <u>Probability</u>

Black: P(B~) = 5/13   Black: P(B~₂/B~₁) = 19/51    B~,B~    (5/13) x (19/51) = 95/663

*************************************************************************************************

(ii) A deck of cards contains 4 Aces out of 52 total cards

1st draw: 4 Aces out of 52 total cards → 4/52 = 1/13

2nd draw: 1 Queen of Hearts out of 51 total remaining cards  →  1/51

  <u>1st Draw </u>                 <u>2nd Draw </u>                   <u>Outcome</u>         <u>Probability</u>

 Ace: P(A) = 1/13      Qh: P(Qh₂/A₁) = 1/51   Ace,Queen(h)   (1/13) x (1/51) = 1/663

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4 years ago
How to write 25 percent of N
Eva8 [605]
25÷100=0.25 0.25×n=the percentage Or 0.25n Or 0.25•n
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