It dose not matter what letter or symbol to find the unknown number because you are only using something to represent that number.
Answer:
No solution would mean that there is no answer to the equation. It is impossible for the equation to be true no matter what value we assign to the variable. Infinite solutions would mean that any value for the variable would make the equation true. ... Note that we have variables on both sides of the equation.
Step-by-step explanation:
<span>For 1 sale, an employee earns 1 tokens.
For 2 sales, an employee earns 6 tokens.
For 3 sales, an employee earns 12 tokens.
For 4 sales, an employee earns 19 tokens.
</span>
For the answer to the question above,
Suppose that for x sales the number of tokens the employee earns is:
ax^3 + bx^2 + cx + d
Therefore:
a(1^3) + b(1^2) + c(1) + d = 1
a(2^3) + b(2^2) + c(2) + d = 6
a(3^3) + b(3^2) + c(3) + d = 12
a(4^3) + b(4^2) + c(4) + d = 19
Therefore:
a + b + c + d = 1
8a + 4b + 2c + d = 6
27a + 9b + 3c + d = 12
64a + 16b + 4c + d = 19
Solve that to get:
a = 0
b = 1/2
c = 7/2
d = -3
Therefore, the formula is:
(1/2)x^2 + (7/2)x - 3
Answer:
B. 10 months
Step-by-step explanation:
The balance on the loan will be ...
b = 1600 - 80t . . . . . . where t is the number of months of payments
The balance in the savings account will be ...
s = 500 + 25t
The savings account balance will be at least as much as the loan balance when ...
s ≥ b
500 +25t ≥ 1600 -80t . . . substitute the account balance expressions
105t ≥ 1100 . . . . . . . . . . . . add 80t -500
t ≥ 1100/105 ≈ 10.48 ≈ 10
It will take Josh 10 months to have enough savings to pay the loan in full.
_____
<em>Comment on rounding</em>
IMO, it makes no sense to round down, as Josh will NOT have enough in 10 months. He will have enough after he makes one more payment of $80. At 10 months, the loan balance is $50 more than the savings balance. It will be 11 months before there is enough savings to pay off the loan.