Answer: (3,-2)
Step-by-step explanation:
Let the three integers be x - 1 x and x + 1
(x - 1)(x + 1) = 6x + 6
x^2 - 1 = 6x + 6
x^2 - 6x - 7 = 0
(x - 7)(x + 1) = 0
x - 7 = 0
x = 7
x + 1 = 0
x = - 1
the solutions are (7,0) and (-1,0)
Answer:
14 + 25l + 6l^2
Step-by-step explanation:
(7 + 2i) (2 + 3i)
=> 14 + 4l + 21l + 6l^2
=> 14 + 25l + 6l^2
This is the correct answer
Answer with Step-by-step explanation:
Let x and y are two numbers
According to question
....(1)
Suppose x is larger than y
![x^2=x(4y+8x)](https://tex.z-dn.net/?f=x%5E2%3Dx%284y%2B8x%29)
![x=4y+8x](https://tex.z-dn.net/?f=x%3D4y%2B8x)
![x-8x=4y](https://tex.z-dn.net/?f=x-8x%3D4y)
![-7x=4y](https://tex.z-dn.net/?f=-7x%3D4y)
![y=-\frac{7}{4}x](https://tex.z-dn.net/?f=y%3D-%5Cfrac%7B7%7D%7B4%7Dx)
Substitute the value of y
![x^2+(-\frac{7}{4}x)^2=100](https://tex.z-dn.net/?f=x%5E2%2B%28-%5Cfrac%7B7%7D%7B4%7Dx%29%5E2%3D100)
![x^2+\frac{49}{16}x^2=100](https://tex.z-dn.net/?f=x%5E2%2B%5Cfrac%7B49%7D%7B16%7Dx%5E2%3D100)
![\frac{16x^2+49x^2}{16}=100](https://tex.z-dn.net/?f=%5Cfrac%7B16x%5E2%2B49x%5E2%7D%7B16%7D%3D100)
![\frac{65}{16}x^2=100](https://tex.z-dn.net/?f=%5Cfrac%7B65%7D%7B16%7Dx%5E2%3D100)
![x^2=\frac{16\times 100}{65}](https://tex.z-dn.net/?f=x%5E2%3D%5Cfrac%7B16%5Ctimes%20100%7D%7B65%7D)
![x=\sqrt{\frac{1600}{65}}=\frac{40}{\sqrt{65}}=\frac{40}{65}\sqrt{65}=\frac{8}{13}\sqrt{65}](https://tex.z-dn.net/?f=x%3D%5Csqrt%7B%5Cfrac%7B1600%7D%7B65%7D%7D%3D%5Cfrac%7B40%7D%7B%5Csqrt%7B65%7D%7D%3D%5Cfrac%7B40%7D%7B65%7D%5Csqrt%7B65%7D%3D%5Cfrac%7B8%7D%7B13%7D%5Csqrt%7B65%7D)
![y=-\frac{7}{4}\times \frac{8}{13}\sqrt{65}=-\frac{14}{13}\sqrt{65}](https://tex.z-dn.net/?f=y%3D-%5Cfrac%7B7%7D%7B4%7D%5Ctimes%20%5Cfrac%7B8%7D%7B13%7D%5Csqrt%7B65%7D%3D-%5Cfrac%7B14%7D%7B13%7D%5Csqrt%7B65%7D)