Answer:
The vertex is located on the x-axis between the second and third quadrants
Step-by-step explanation:
Whereby the function is f(x) = (x + 3)², we have;
f(x) = (x + 3)² = x² + 6·x + 9
The vertex, (h, k), of the quadratic function given in general form, a·x² + b·x + c is found as follows;
h = -b/(2·a) and k = f(h)
Therefore by comparison of the given quadratic function and the general form of a quadratic function, we have;
a = 1, b = 6, c = 9
h = -6/(2 × 1) = -3
k = f(-3) = (-3)² + 6 × (-3) + 9 = 0
The vertex (h, k) = (-3, 0)
Therefore, the location of the vertex is on the x-axis axis between the second and the third quadrant.
