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3 years ago

I need some help with this

Mathematics

1 answer:

dalvyx [7]3 years ago

4 0

$\pink{\underline{{\boxed{\bf{QUESTION: }}}}}$

-6(x+4) = _____

$\pink{\underline{{\boxed{\bf{OPTIONS:}}}}}$

6x - 4❌
-6x + 4❌
-6x - 24✔️
6x + 24❌

$\pink{\underline{{\boxed{\bf{ ANSWER: }}}}}$

-6(x+4) = <u>-6x - 24</u>

<h3>Hope It's helped! :)</h3>

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What is the algebraic expression for: four less than three times the number of egg orders and six more than two times the number

Ira Lisetskai [31]

3n - 4 + 6 + 2n

I believe that's the answer!

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3 years ago

Please help, due today

patriot [66]

Answer:

I am a little late but here is the answer

The graph of a non-proportional linear relationship is a straight line that does not pass through the origin.

Non-proportional linear relationships can be expressed in the form y = m x + b

With increase in proportion of one quantity, the proportion of the other quantity decreases and with decrease in proportion of one quantity , the proportion of the other quantity increases .

Step-by-step explanation:

From Graph :

The graph of a non-proportional linear relationship is a straight line that does not pass through the origin.

From Equation :

Non-proportional linear relationships can be expressed in the form y = m x + b, where , m is the slope of the line, and b represents the y-intercept.

From Table:

With increase in proportion of one quantity, the proportion of the other quantity decreases and with decrease in proportion of one quantity , the proportion of the other quantity increases .

4 0

3 years ago

Find x?<br> In 3x - In(x - 4) = ln(2x - 1) +ln3

earnstyle [38]

Answer:

$x = \displaystyle \frac{5 + \sqrt{17}}{2}$ .

Step-by-step explanation:

Because $3\, x$ is found in the input to a logarithm function in the original equation, it must be true that $3\, x > 0$ . Therefore, $x > 0$ .

Similarly, because $(x - 4)$ and $(2\, x - 1)$ are two other inputs to the logarithm function in the original equation, they should also be positive. Therefore, $x > 4$ .

Let $a$ and $b$ represent two positive numbers (that is: $a > 0$ and $b > 0$ .) The following are two properties of logarithm:

$\displaystyle \ln (a) + \ln(b) = \ln\left(a \cdot b\right)$ .

$\displaystyle \ln (a) - \ln(b) = \ln\left(\frac{a}{b}\right)$ .

Apply these two properties to rewrite the original equation.

Left-hand side of this equation:

$\begin{aligned}&\ln(3\, x) - \ln(x - 4)= \ln\left(\frac{3\, x}{x -4}\right)\end{aligned}$

Right-hand side of this equation:

$\ln(2\, x- 1) + \ln(3) = \ln\left(3 \left(2\, x - 1\right)\right)$ .

Equate these two expressions:

$\begin{aligned}\ln\left(\frac{3\, x}{x -4}\right) = \ln(3(2\, x - 1))\end{aligned}$ .

The natural logarithm function $\ln$ is one-to-one for all positive inputs. Therefore, for the equality $\begin{aligned}\ln\left(\frac{3\, x}{x -4}\right) = \ln(3(2\, x - 1))\end{aligned}$ to hold, the two inputs to the logarithm function have to be equal and positive. That is:

$\displaystyle \frac{3\ x}{x - 4} = 3\, (2\, x - 1)$ .

Simplify and solve this equation for $x$ :

$x^2 - 5\, x + 2 = 0$ .

There are two real (but not rational) solutions to this quadratic equation: $\displaystyle \frac{5 + \sqrt{17}}{2}$ and $\displaystyle \frac{5 - \sqrt{17}}{2}$ .

However, the second solution, $\displaystyle \frac{5 - \sqrt{17}}{2}$ , is not suitable. The reason is that if $x = \displaystyle \frac{5 - \sqrt{17}}{2}$ , then $(x - 4)$ , one of the inputs to the logarithm function in the original equation, would be smaller than zero. That is not acceptable because the inputs to logarithm functions should be greater than zero.