Answer:
No, you would multiply by 1.15
Step-by-step explanation:
A percentage goes by 'Hundreths' or .01
So 15% would be .15
We don't want to lose money along the way so we add a 1 it so it goes up for the total, like this:
28.75 * 1.15 = 33.1
Let the wire left be x yards.
Therefore, the answer of your question will be x yards.
Answer = x yards
Answer:
<h3>perpendicular line:
y = -¹/₆
x + 4¹/₃
</h3><h3> parallel line:
y = 6x - 45
</h3>
Step-by-step explanation:
y=m₁x+b₁ ⊥ y=m₂x+b₂ ⇔ m₁×m₂ = -1
{Two lines are perpendicular if the product of theirs slopes is equal -1}
y = 6x - 7 ⇒ m₁=6
6×m₂ = -1 ⇒ m₂ = -¹/₆
The line y=-¹/₆
x+b passes through point (8, 3) so the equation:
3 = -¹/₆
×8 + b must be true
3 = -⁴/₃ + b
b = 4¹/₃
Therefore equation in slope-intercept form:
y = -¹/₆
x + 4¹/₃
y=m₁x+b₁ ║ y=m₂x+b₂ ⇔ m₁ = m₂
{Two lines are parallel if their slopes are equal}
y = 6x - 7 ⇒ m₁=6 ⇒ m₂=6
The line y=6x+b passes through point (8, 3) so the equation:
3 = 6×8 + b must be true
3 = 48 + b
b = -45
Therefore equation in slope-intercept form:
y = 6x - 45
The more appropriate measures of center and spread are:
- A. Better measure of spread: the interquartile range (IQR)
- B. Better measure of center: the median
<h3>Which measures are best for the given data?</h3>
The better measure of the middle would be the median because mean is affected by low and high values which are present in the given data set.
As mean is not being used, standard deviation should not be used for the same reason. This leaves us with the interquartile range which is best because it does not take outliers into account.
Find out more on the Interquartile Range at brainly.com/question/12568713.
#SPJ1
Answer:
Area=88in squared
Step-by-step explanation:
