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zlopas [31]
3 years ago
12

Liz earns a salary of $2,100 per month, plus a commission of 5% of her sales. She wants to earn at least $2,400 this month. How

do you write an inequality to find amounts of sales that will meet her goal?
Mathematics
1 answer:
Nookie1986 [14]3 years ago
7 0
Hello! She earns a salary of $2,100, which is the fixed amount each month, plus 5% commission on her sales. To find out the amount of sales that will help her reach her goal, set up the inequality like this:

2,100 + 0.05x ≥ 2,400

We set it up like this, because $2,100 is the one-time price per month, and she earns 5% of her sales as commission. Plus, the key words "at least" means the inequality sign is greater than or equal to (≥)

How to solve this:

First off, subtract 2,100 from both sides, when you do, you get 0.05x ≥ 300. Now, divide each side by 0.05 to isolate the "x". 300/0.05 is 6,000. Let's check this. 6,000 * 5% (0.05) is 300. There. x = 6,000. Liz will need to sell $6,000 worth of items this month in order to meet her goal.
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If a woman making $45 an hour gets a 10% eaise how much additional money is she making.


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HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
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Answer:

D. reflection across a vertical line

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3 0
3 years ago
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A random sample of 121 automobiles traveling on an interstate showed an average speed of 73 mph. from past information, it is kn
tatiyna

121 is big enough to assume normality and not worry about the t distribution. By the 68-95-99.7 rule a 95% confidence interval includes plus or minus two standard deviations. So 95% of the cars will be in the mph range


(73 - 2 \cdot 11, 73 + 2 \cdot 11) = (51,95)


The question is a bit vague, but it seems we're being asked for the 95% confidence interval on the average of 121 cars. The 121 is a hint of course.


The standard deviation of the average is in general the standard deviation of the individual samples divided by the square root of n:


\sigma = \dfrac{ 11}{\sqrt{121}} = 1


So repeating our experiment of taking the average 121 cars over and over, we expect 95% of the averages to be in the mph range


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That's probably the answer they're looking for.



4 0
3 years ago
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