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Rina8888 [55]
3 years ago
13

If you’re the victim of cyber bullying behavior, besides contacting your teacher or the school, where else can you go to find in

formation?
Computers and Technology
1 answer:
RideAnS [48]3 years ago
3 0

parents

childline

ceop

family

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What is the command to create a compressed archive(archive1.tar.gz) of files test1 test2and test3.
yulyashka [42]

Answer:

The command to create a compressed archive (archive1.tar.gz) is

tar\,\,-czvf\,\,archive1.tar.gz\,\,test1\,\,test2\,\,test3

Explanation:

The explanation for the above command is

The general command to create a compressed archive is

tar -czvf name-of-archive.tar.gz /path/to/directory-or-files

Here, the terms are as follows:

-c : Creates an archive

-z : Compress the archive with gzip.

-v : This is known as verbose. This is an optional command and it displays the progress on terminal command. Without this the progress is not displayed on terminal command.

-f : Allows to specify the file name of the archive.

Here, if we want to archive multiple files, we provide the command the names of multiple files or directories of the files also can be used.

So, the command tar\,\,-czvf\,\,archive1.tar.gz\,\,test1\,\,test2\,\,test3

creates a compressed archive  - archive1.tar.gz of files test1, test2 and test3.

 

7 0
3 years ago
Join my discord server! CODE IS (CebjBXN)​
11Alexandr11 [23.1K]

Answer:

sure

Explanation:

7 0
3 years ago
Read 2 more answers
Security controls are measures taken to protect systems from attacks on the integrity, confidentiality, and availability of the
Delvig [45]

Answer:

The correct option is D: Administrative controls

Explanation:

Administrative controls are also known as work practice controls and involves changes in the procedure of work such as rules, schedules, policies, training etc, with the intention of cutting down to the barest minimum incidence, duration, and the graveness of exposure to situations or chemical that constitute a hazard. Drug screening test would be to ensure that the employee is fit to work and does not form a hazard and thus is an administrative control.

4 0
3 years ago
1D Array Assignment Outcome: Student will demonstrate the ability to use a one-dimensional array. Student will demonstrate the a
sukhopar [10]

Answer:

Program to this question as follows:

program:

import java.util.*; //import package for user input

public class Main  //defining class  

{

public static void main(String[] as)//defining main function

{//defining integer array

int [] num = new int[113];  

boolean find_in = false; //defining boolean variable

int [] counts = new int[101];//defining integer array

int y, tem = 0, counter = 0,in=0,x,find; //defining integer variable

Scanner ox= new Scanner(System.in); //creating Scanner class Object

while(counter <= 112) //loop to check condition

{

num[counter++] = generateRandomNumber(); //using array to hold random function value.  

}

System.out.println("The array:"); //message

for(x = 0; x < 112; x++) // loop to count the value

{

if(x != 0 && x % 9 == 0) // if block to chek value

System.out.println(); // print  

else

System.out.print(num[x] + " "); // print array

}

// sort in ascending order

Arrays.sort(num); //using sort method

System.out.print("\n\nThe array in sorted order:"); // print value

for( x = 0; x < num.length; x++) // loop uses if block to check value is divisiable by 9  

{

if(x % 9 == 0) //check condition  

System.out.println(); // print  

else

System.out.print(num[x] + " "); // print array

}

// search for a number

System.out.print("\n\nEnter a number to search: "); // print message

find= ox.nextInt(); // input number by user

for(x= 0;x< num.length;x++) //loop to count values

{

if(num[x] == find) //check value

{

find_in = true; //change value

in= x;

break; //using break keyword

}

}

if(find_in)  //find value

System.out.println(find + " is found at index " + in); // print location

else

System.out.println("Not found"); //message

// display count of each numbers

System.out.println("Count of each numbers:"); //message

for(y = 1; y< num.length; y++) // loop to store element in counts array  

{

tem = num[y]; //hold value

counts[tem]++; //increment value

}

for(x = 1; x< counts.length; x++) //loop to print value

{

System.out.println(x + ": " + counts[x]); // print value

}

// average of the numbers in the array

for(x = 0; x < num.length; x++) // loop to calculate sum and average

{

sum += num[x]; //calculate sum

}

avg = (sum / 100); // calculate avg

System.out.println("\nThe average of the numbers in the array: " + avg);

// highest number in the array

int high= num[0]; //find number

for(x= 0;x < num.length;x++)

{

if(num[x] > high)

high = num[x]; //hold value of highest Number

}

System.out.println("\nThe highest number is: " + high); //print value

int low = num[0]; // defining variable for lowest number

for(x= 0; x < num.length - 1; x++) // loop to calculate lowest number

{

if(num[x] < low) //condition for lowest number

low = num[x]; //hold lowest number

}

System.out.println("\nThe lowest number is: " + low); //print value

}

public static int generateRandomNumber() //defining function  

{

Random ra = new Random(); //creating Random function Object

return (ra.nextInt(100)+ 1); //input and return value

}

}

Output:

the output of the given code is display in image

Explanation:

In the above program, an array is declared that uses a random function to input the number, in the next step the sort function is used, that sorted all array elements, in the next step the scanner class is used, that input the number form the user ends and pass search in the sorted array.

  • After searching the average of array elements is calculated. In this array we calculate the highest and lowest number of the array to print all the values the print method is used.
  • At the last, the rand method is used that generates the random number for the array and passes into a num array that prints the values.

7 0
3 years ago
The binary number represented by the voltage graph below is
Delicious77 [7]

Answer:

4

Explanation:

5 0
2 years ago
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